T over x is your starting debut
add 40 from your original answer and divide by two
triplemente the second number and switch your trinomial by three
Answer:
Step-by-step explanation:
- −5.93 + (−8.62) + 5.93 =
- −5.93 - (8.62 - 5.93) = B
- −(5.93 + 8.62) + 5.93 = C
- −5.93 −8.62 - (- 5.93) = D
- -8.62 A
0.96 or 19/20
0.96 as fraction = 96/100 = 19.2 / 20 5 into 96 is 19.2 and 5 into 100 is 20
So 0.96 is the same as 19.2/20
Since 19.2 / 20 and 19 / 20 have the same denominator, therefore the 19.2 / 20 is bigger than 19 / 20.
So the 0.96 is bigger than the 19 / 20.
Answer:
Option B.
Step-by-step explanation:
It is given that ΔSRQ is a right angle triangle, ∠SRQ is right angle.
RT is altitude on side SQ, ST=9, TQ=16 and SR=x.
In ΔSRQ and ΔSTR,
(Reflexive property)
(Right angle)
By AA property of similarity,
Corresponding parts of similar triangles are proportional.
Substitute the given values.
On cross multiplication we get
Taking square root on both sides.
The value of x is 15. Therefore, the correct option is B.
Given:
2 parallelograms with an area of 9 1/3 yd²
height of each parallelogram is 1 1/3 yd
Area of parallelogram = base * height
We need to divide the combined area into two to get each parallelogram's base.
9 1/3 = ((9*3)+1)/3 = 28/3
28/3 ÷ 2 = 28/3 * 1/2 = 28/6 yd² or 4 4/6 yd² ⇒ 4 2/3 yd²
Area of each parallelogram is 4 2/3 yd²
4 2/3 yd² = base * 1 1/3 yd
14/3 yd² ÷ 4/3 yd = base
14/3 yd² x 3/4 yd = base
14*3 / 3*4 = base
42 / 12 = base
3 6/12 yd = base
or 3 1/2 yd = base
a) the base of each parallelogram is 3 1/2 yards
b) we can assume that the two parallelograms form a rectangle.
area of a rectangle is length times width.
length is 3 1/2 yds * 2 = 7 yds
width is 3 1/2 yds
Area of rectangle = 7 yds * 3 1/2 yds
Area = 7 yd * 7/2 yd
Area = 7*7 / 2 yd²
Area = 49 / 2 yd²
Area = 24 1/2 yd²
