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2 years ago

11

While scuba diving, Rajeev dove to a depth of 12.6 feet below the surface of the water and then descended another 8.7 feet. What

expression can be used to find Rajeev’s new position?

2 answers:

VARVARA [1.3K]2 years ago

6 0

12.6+8.7=X X being his new position

bezimeni [28]2 years ago

6 0

Answer:

y=-12.6+(-8.7)

Step-by-step explanation:

Given : While scuba diving, Rajeev dove to a depth of 12.6 feet below the surface of the water and then descended another 8.7 feet.

To find : What expression can be used to find Rajeev’s new position?

Solution :

Rajeev dove to a depth of 12.6 feet below the surface of the water.

i.e, it dove downward means -12.6 feet.

Then descended another 8.7 feet.

i.e, again he dove downward means -8.7 feet.

The expression used to find the Rajeev’s new position is

y= -12.6 feet +(-8.7)feet

or y=-12.6-8.7

y=−21.3 feet

i.e, 21.3 feet down he is from the surface of water.

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(0,346)(2,344.8)
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y = mx + b
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use either of ur points (0,346)...x = 0 and y = 346
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346 = b

so ur equation is : y = -0.6x + 346

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