1. The formula for calculate the area of a rectangle, is:
A=LxW
A is the area of the rectangle
L is the length of the rectangle.
W is the widht of the rectangle
2. You have that:
-The<span> rectangular Corn Hole area has a width of 5 feet and a length of 10 feet, so:
L1=10 feet
W1=5 feet
- When</span> a uniform amount is added to each side (x), the area is increased to 84 feet². Then, you have a different length (L2) and a different width (W2):
3. The new length is:<span>
L2=L1+x+x
L2=L1+2x
L2=10+2x
4. The new width is:
W2=W1+x+x
W2=W1+2x
W2=5+2x
5. The new area is:
A2=84 feet</span>²<span>
6. Then, you have:
A=LxW
84</span>=(10+2x)(<span>5+2x)
7. When you apply the distributive property, you obtain a quadratic equation:
4x</span>²+30x-34=0
<span>
8. You can solve with by applyin the quadratic formula:
x=(-b±√(b^2-4ac))/2a
a=4
b=30
c=-34
9. Then, the answer is:
x=1 feet
</span><span>
</span>
Answer:
$24166.67
Step-by-step explanation:
$25 per hour and works 35 hours per week
Norma Jean makes 35 * 25 (<em>without sales) = </em>$875
<em> </em>Total commission made by Norma<em> </em>= 4500-875 = $3625
<em>let total number of sales by Norma be x</em>
15% is the same as 15/100
<em>so </em>(15/100) * x =3625 <em> multiplying both sides by 100</em>
15x = 362500<em> making x subject of formula</em>
x = 362500/15
x = 24 166.67
Norma should sell total items worth $24166.67
Answer:
Step-by-step explanation: Uhh I have no idea how I got this right because I guessed but
small: 3-5 pounds 0.25+1.2+2.7
Medium: 5-8 pounds 0.25+0.25+1.2+1.2+1.2+1.2
Large 8-10 pounds 0.25+1.2+1.2+1.2+2.7+2.7
Hope I helped this is my first time answering a question have a good day everyone
Answer:
Given Polynomial:
Factors of Coefficient of terms
80 = 5 × 16
32 = 2 × 16
48 = 3 × 16
Common factor of the coefficient of all term is 16.
Each term contain variable. So the Minimum power of b is common from all terms.
Common from all variable part comes b².
So, Common factor of the polynomial = 16b²
⇒ 16b² ( 5b² ) - 16b² ( 2c³ ) + 16b² ( 3b²c )
⇒ 16b² ( 5b² - 2c³ + 3b²c )
Therefore, Statements that are true about David's word are:
The GCF of the coefficients is correct.
The variable c is not common to all terms, so a power of c should not have been factored out.
In step 6, David applied the distributive property
