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nikklg [1K]
1 year ago
14

What is the final transformation in the composition of transformations that maps pre-image GHJK to image G'H"J"K"? a translation

to the right a reflection across line m a 90° rotation about point G a 180° rotation about point G

Mathematics
2 answers:
kramer1 year ago
5 0

Answer:

B

Step-by-step explanation:

trust meee

tamaranim1 [39]1 year ago
3 0

Answer:

a reflection across line m answer is b

Step-by-step explanation:

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Jerry and Katja are running in a race. Jerry runs really fast for a while. Then, he stops to catch his breath. After he has rest
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How would u find 4 1\5 divided by 2 1\3
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Remmber
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)
conver to improper

4 and 1/5=20/5+1/5=21/5
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(21/5)/(7/3)=(21/5)(3/7)=63/35=9/5=1 and 4/5
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How to factorise 5h^2-12hg​
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Answer:

h(5h-12g)

Step-by-step explanation:

5h^2-12hg

When we factor expressions, we look for factors within the terms that are alike, or in other words, we look for common factors. Here, 5h^2 and 12hg only have one common factor: h. Therefore, to factorize this expression, divide both terms by h.

= h(\frac{5h^2}{h}-\frac{12hg}{h}  )\\= h(5h-12g)

Now, we've "carried" h out of the expression and have therefore factored it.

I hope this helps!

7 0
1 year ago
A coordinate plane with a line passing through (negative 4, 3), (0, 1), and (4, negative 1). Which linear function is represente
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Answer:

Step-by-step explanation:

If these 3 points are collinear, then we can find the slope of the linear function using any 2 of those points.  Suppose we use (-4, 3) and (0, 1):  

As we move from (-4, 3) to (0, 1), x increases by 4 and y decreases by 2.  Hence, the slope of this lilne is m  = rise/run = -2/4, or m = -1/2.

Using the slope-intercept formula y = mx + b and replacing y with 1, x with 0 and m with -1/2, we get:

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1 year ago
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You have two circles, one with radius r and the other with radius R. You wish for the difference in the areas of these two circl
gtnhenbr [62]

Answer:

maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

Step-by-step explanation:

We know that area of circle is given by

A=\pi \times (radius)^{2}

For circle with radius 'r' we have

A_{1}=\pi \times (r)^{2}

For circle with radius 'R' we have

A_{2}=\pi \times (R)^{2}

Now according to given condition we have

A_{1}-A_{2}\leq \frac{5}{\pi }

\Rightarrow \pi r^{2}-\pi R^{2}\leq \frac{5}{\pi }\\\\\Rightarrow (r^{2}-R^{2})\leq \frac{5}{\pi ^{2}}\\\\(r+R)(r-R)\leq \frac{5}{\pi ^{2}}\\\\\because (a^{2}-b^{2})=(a+b)(a-b)\\\\(r+R)=10(Given)\\\\\Rightarrow(r-R)\leq \frac{5}{10\pi ^{2}}\\\\\therefore (r-R)\leq\frac{1}{2\pi ^{2}}

Thus maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

6 0
2 years ago
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