7. In the figure below, lines p and q are parallel. The measure of 23 = 126°.

PLEASE HELP DUE TODAY ILL GIVE BRAINLIEST 1. An advertising company charges $40 per half-page advertisement and $75 per full-pag

Oksana_A [137]

Answer: inverse of given function = log(x)/log(3)

Step-by-step explanation: how to find the inverse of any function?

in the complete function, replace y with "x" and x with "y"then, solve the obtained equation from step 2 for yand, then the value obtained for "y" is the inverse required i.e. = f^{-1}(x)

now, we solve the problem:

given : - y = 3^x

replacing the value of "y" with "x", we get,

x = 3^y

to solve for "y" we should take the "logarithm" for both sides

log (x) = y log(3)

or y = log(x)/log(3)

or f^(-1) (x) = log(x)/log(3)

( I hope this helped <3 )

8 0

2 years ago

A survey of 100 people found that 35 people exercise in the morning, 45 people exercise in the afternoon, and 20 people exercise

marissa [1.9K]

100 total people......35 exercise in the morning....45 in the afternoon...and 20 at night

Jim is correct.....
35/100 is the ratio of people who exercise in the morning to total people.
45/100 is the ratio of afternoon exercisers to total people
20/100 is the ratio of night exercisers to total people

7 0

2 years ago

Read 2 more answers

A wheat farmer cuts down the stalks of wheat and gathers them in 200 piles. The 200 gathered piles will be put on a truck. The t

denpristay [2]

Answer:

Check the explanation

Step-by-step explanation:

We want to estimate the total weight of grain on the field based on the data on a simple random sample of 5 piles out of 200. The population and sample sizes are N=200 & n=5 respectively.

1) Let Y_1,Y_2,...,Y_{200} be the weight of grain in the 200 piles and y_1,y_2,...,y_{5} be the weights of grain in the pile from the simple random sample.

We know, the sample mean is an unbiased estimator of the population mean. Therefore,

$\widehat{\mu}=\overline{y}=\frac{1}{5}\sum_{i=1}^{5}y_i=\frac{1}{5}(3.3+4.1+4.7+5.9+4.5)=4.5$

where \mu is the mean weight of grain for all the 200 piles.

Hence, the total grain weight of the population is

$\widehat{Y}=Y_1+Y_2+...+Y_{200}$

= $200\times \widehat{\mu}\: \: \: =200\times 4.5\: \: \: =900\, lbs$

2) To calculate a bound on the error of estimates, we need to find the sample standard deviation.

The sample standard deviation is

S= $\sqrt{\frac{1}{5-1}\sum_{i=1}^{5}(y_i-\overline{y})^2}\: \: \: =0.9486$

Then, the standard error of $\widehat{Y} is$

$\sigma_{\widehat{Y}} =\sqrt{\frac{N^2S^2}{n}\bigg(\frac{N-n}{N}\bigg)}\: \: \:$ =83.785

Hence, a 95% bound on the error of estimates is

$[\pm z_{0.025}\times \sigma_{\widehat{Y}}]\: \: \: =[\pm 1.96\times 83.875]\: \: \: =[\pm 164.395]$

3) Let x_1,x_2,...,x_5 denotes the total weight of the sampled piles.

Mean total weight of the sampled piles is

$\overline{x}=\frac{1}{5}\sum_{i=1}^{5}x_i=45$

The sample ratio is

$r=\frac{\overline{y}}{\overline{x}}=\frac{4.5}{45}$ =0.1 , this is also the estimate of the population ratio R= $\frac{\overline{Y}}{\overline{X}} .$

Therefore, the estimated total weight of grain in the population using ratio estimator is

$\widehat{Y}_R\: \: =r\times 8800\: \: =0.1\times 8800\: \: =880\,$ lbs

4) The variance of the ratio estimator is

var(r)= $\frac{N-n}{N}\frac{1}{n}\frac{1}{\mu_x^2}\frac{\sum_{i=1}^{5}(y_i-rx_i)^2}{n-1} , where \mu_x=8800/200=44lbs$

= $\frac{200-5}{200}\, \frac{1}{5}\: \frac{1}{44^2}\, \frac{0.2}{5-1}=0.000005$

Hence, the standard error of the estimate of the total population is

$\sigma_R=\sqrt{X^2 \: var(r)}\: \: \: =\sqrt{8800^2\times 0.000005}\: \: \:$ =21.556

Hence, a 95% bound on the error of estimates is

$[\pm z_{0.025}\times \sigma_{R}]\: \: \: =[\pm 1.96\times 21.556]\: \: \: =[\pm 42.25]$

8 0

2 years ago

Read 2 more answers

A teacher handed out m notebooks which came in packs with c notebooks in each pack. How many packs were there?

Roman55 [17]

Let’s throw some numbers in here just so it becomes clear what we are asked for.

Let’s say the teacher hands out 12 notebooks that came in packs with 4 notebooks in each pack. If you are asked for the number of packs here you would see that it’s 3. That is 3 packs of 4 give 12.

So you divide the number of notebooks handed out (m) by the number of notebooks per pack (c) to get the number of packs.

The number of packs is m/c

7 0

2 years ago

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Ariel left her home at 9 a.m., driving at 45 mph. At 11 a.m. her brother left the home and started after her at 60 mph. At what

Vlada [557]

Answer:

5:00 pm

Step-by-step explanation:

Let

x -----> the umber of hours

y ----> the total distance in miles

we know that