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1 year ago

7. In the figure below, lines p and q are parallel. The measure of 23 = 126°.

Mathematics

1 answer:

damaskus [11]1 year ago

8 0

Answer:

You just subtract 126 degrees from 180 degrees = 34 degrees for all angles

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Triangle J K L is shown. Angle K L J is a right angle. The length of hypotenuse K J is 10.9 centimeters and the length of L J is

scZoUnD [109]

Answer:

sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x

Step-by-step explanation:

From the given triangle JKL;

Hypotenuse KJ = 10.9

Length LJ is the opposite = 8.9cm

The angle LKJ is the angle opposite to side KJ = x

Using the SOH CAH TOA Identity;

sin theta = opp/hyp

sin LKJ = LJ/KJ

Sinx = 8.9/10.9

x = arcsin(8.9/10.9)

sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x

7 0

2 years ago

Read 2 more answers

100/225 square feet of your bakery will be used as your storefront, where customers come visit. The rest kill be used for storag

Lelu [443]

The answer is 5/9. I showed a bit more work on the other post

7 0

2 years ago

Which is equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x?

sergeinik [125]

Solving RootIndex 3 StartRoot 8 EndRoot Superscript x we get $=2^x$

Step-by-step explanation:

We need to find equivalent to RootIndex 3 StartRoot 8 EndRoot Superscript x

Writing in mathematical form:

$(\sqrt[3]{8})^x$

Solving:

We know 8= 2x2x2= 2^3

and $\sqrt[3]{x}=x^{\frac{1}{3}}$

Applying these rules:

$=((2^3)^{\frac{1}{3}})^x$

$=(2^{\frac{3}{3}})^x\\$

$=2^x$

So, solving RootIndex 3 StartRoot 8 EndRoot Superscript x we get $=2^x$

Keywords: Radical Expression

Learn more about Radical Expression at:

#learnwithBrainly

8 0

1 year ago

25. To produce the graph of the function y=0.5cos(0.5x), what transformations should be applied to the graph of the parent funct

soldi70 [24.7K]

Answer:

C. A horizontal stretch to produce a period of $2\pi$ and a vertical compression.

Step-by-step explanation:

We are given the parent function as $y= \cot x$

It is given that, transformations are applied to the parent function in order to obtain the function $y=0.5\cot (0.5x)$ i.e. $y=\frac{1}{2}\cot (\frac{x}{2})$

That is, we see that,

The parent function $y= \cot x$ is stretched horizontally by the factor of $\frac{1}{2}$ which gives the function $y=\cot (\frac{x}{2})$ .

Further, the function is compressed vertically by the factor of $\frac{1}{2}$ which gives the function $y=\frac{1}{2}\cot (\frac{x}{2})$ .

Now, we know,

If a function f(x) has period P, then the function cf(bx) will have period $\frac{P}{|b|}$ .

Since, the period of $y= \cot x$ is $\pi$ , so the period of $y=\frac{1}{2}\cot (\frac{x}{2})$ is $\frac{\pi}{1/2}$ = $2\pi$

Hence, we get option C is correct.

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2 years ago

We know that a triangle with side lengths x2 -1, 2x, and x2 1 is a right triangle. Using those side lengths, find the missing tr

Olenka [21]

Least to greatest, the triples are (2x, x²-1, x²+1). Thus the value in the first column of the table is half the value of the first of the triples. Your completed table will be

$\begin{array}{cc}\text{x-value}&\text{triple}\\3&\bf{(6,8,10)}\\\bf{4}&(8,15,17)\\5&\bf{(10,24,26)}\\\bf{6}&(12,35,36)\end{array}$

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2 years ago