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Gala2k [10]
2 years ago
6

The volume of the rectangular prism is 32 cubic feet more than the volume of the right triangular prism. Find the volume of each

figure. Rectangular prism: L= 6 ft. W= x H=3 ft. Triangular Prism: L= 7 ft W= x H=4 ft. Volume of rectangular prism: _ ft3 Volume of triangular prism: _ ft3 PLEASE ANSWER ASAP! I'M OFFERING A LOT OF POINTS!
Mathematics
2 answers:
Art [367]2 years ago
4 0

Answer:

Step-by-step explanation:

Let the volume of a rectangular prism be VR and that of right triangular prism be VT. If The volume of the rectangular prism is 32 cubic feet more than the volume of the right triangular prism, then VR = 32 + VT

Since VR = length * width and height

VR = 6*x*3

VR = 18x ft³

Also VT =  Length *width * Height/2

VT = (7 * x * 4)/2

VT = 28x/2

VT = 14xft³

Since VR = 32 + VT

18x = 32+(14x)

collect like terms

18x-14x = 32

4x = 32

divide both sides by 4

4x/4 = 32/4

x = 8

Volume of the rectangular prism = 18x

Volume of the rectangular prism = 18*8

Volume of the rectangular prism = 144ft³

Volume of the right triangular prism = 14x

Volume of the rectangular prism = 14*8

Volume of the rectangular prism = 112ft³

jok3333 [9.3K]2 years ago
4 0

Answer:

rectangular is 114ft and triangular is 112ft

Step-by-step explanation:

Let the volume of a rectangular prism be VR and that of right triangular prism be VT. If The volume of the rectangular prism is 32 cubic feet more than the volume of the right triangular prism, then VR = 32 + VT

Since VR = length * width and height

VR = 6*x*3

VR = 18x ft³

Also VT =  Length *width * Height/2

VT = (7 * x * 4)/2

VT = 28x/2

VT = 14xft³

Since VR = 32 + VT

18x = 32+(14x)

collect like terms

18x-14x = 32

4x = 32

divide both sides by 4

4x/4 = 32/4

x = 8

Volume of the rectangular prism = 18x

Volume of the rectangular prism = 18*8

Volume of the rectangular prism = 144ft³

Volume of the right triangular prism = 14x

Volume of the rectangular prism = 14*8

Volume of the rectangular prism = 112ft³

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Mkey [24]

Answer:

rectangles perimeter: 6w

equilateral triangles perimeter: 3w+24

scenario’s equation: 6w=3w+24

Step-by-step explanation:

w=8

rectangles perimeter= 48

EQUTRI perimeter= 48

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Drag the tiles to the correct boxes to complete pair. Two cards are drawn from a well-shuffled standard deck of cards. Match eac
joja [24]

Answer:

The  correct answers are given below

Step-by-step explanation:

In a deck of 52 cards, there are 4 suits of 13 cards

1) Spade(red)

2). Heart(red)

3). Diamonds (red)

4). Clubs (black)

Each suits area ace, king, queen, jack, 10, 9, 8, 7, 6, 5, 4, 3 and 2

To find the probabilities

1). The probability of drawing a red ace followed by another ace of any color without replacement = 2/52 *3/51 = 1/442

2). The probability of drawing a 3 or 5 followed by a 4 or 6 with replacement = 8/52 * 8/52 = 4/169

3). The probability of drawing a king followed by queen with replacement =  4/52 * 4/52 = 1/169

4). The probability of drawing a spade followed by a jack of any color with replacement = 13/52 * 4/52 = 1/52

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Find an equation of the line containing the centers of the two circles whose equations are given below.
Anna35 [415]

Answer:

<h2><em>3y+x = -5</em></h2>

Step-by-step explanation:

The general equation of a circle is expressed as x²+y²+2gx+2fy+c = 0 with centre at C (-g, -f).

Given the equation of the circles x²+y²−2x+4y+1  =0  and x²+y²+4x+2y+4  =0, to  get the centre of both circles,<em> we will compare both equations with the general form of the equation above as shown;</em>

For the circle with equation x²+y²−2x+4y+1  =0:

2gx = -2x

2g = -2

Divide both sides by 2:

2g/2 = -2/2

g = -1

Also, 2fy = 4y

2f = 4

f = 2

The centre of the circle is (-(-1), -2) = (1, -2)

For the circle with equation x²+y²+4x+2y+4  =0:

2gx = 4x

2g = 4

Divide both sides by 2:

2g/2 = 4/2

g = 2

Also, 2fy = 2y

2f = 2

f = 1

The centre of the circle is (-2, -1)

Next is to find the equation of a line containing the two centres (1, -2) and (-2.-1).

The standard equation of a line is expressed as y = mx+c where;

m is the slope

c is the intercept

Slope m = Δy/Δx = y₂-y₁/x₂-x₁

from both centres, x₁= 1, y₁= -2, x₂ = -2 and y₂ = -1

m = -1-(-2)/-2-1

m = -1+2/-3

m = -1/3

The slope of the line is -1/3

To get the intercept c, we will substitute any of the points and the slope into the equation of the line above.

Substituting the point (-2, -1) and slope of -1/3 into the equation y = mx+c

-1 = -1/3(-2)+c

-1 = 2/3+c

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c = -5/3

Finally, we will substitute m = -1/3 and c = 05/3 into the equation y = mx+c.

y = -1/3 x + (-5/3)

y = -x/3-5/3

Multiply through by 3

3y = -x-5

3y+x = -5

<em>Hence the equation of the line containing the centers of the two circles is 3y+x = -5</em>

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The volleyball team at West View High School is comparing T-shirt companies where they can purchase their practice shirts. The t
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10.5x = 7.5x + 30
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x = 30/3
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b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.
Ainat [17]

First box = 14 pounds

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Third Box = x+2= 16 pounds

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<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ 2x

The third box contained two more pounds than the first box i.e.

⇒ x+2

The last box contained one-fourth the amount in the second box i.e.

⇒ (\frac{1}{4})2x = \frac{x}{4}

Therefore , Sum of pounds of candy are :

⇒ \frac{x}{2} +x+2+2x+x=65

⇒ \frac{x}{2} +4x=63

⇒ \frac{9x}{2}=63

⇒ x=63(\frac{2}{9} )

⇒ x=14

Therefore , Candy in each box is :

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

8 0
2 years ago
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