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QveST [7]
2 years ago
15

If f(x)=sinx−1/cos2x, then limx→π2f(x) is equivalent to which of the following?

Mathematics
1 answer:
Harrizon [31]2 years ago
8 0

Answer:

2

Step-by-step explanation:

Given g(x) = sin(x)-1/cos2(x), we are to find the limit if the function g(x) as g(x) tends to π/2

Substituting π/2 into the function

lim x-->π/2 sin(x)-1/cos 2(x)

= sin(π/2) - 1/cos(2)(π/2)

= 1 - 1/cosπ

= 1- 1/-1

= 1 -(-1)

= 1+1

= 2

Hence the limit of the function h(x) = sin(x)-1/cos2(x) as x--> π/2 is 2

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15) Bob has 12 black pen, 14 red pen, 15 green pens, 24 blue pens and 3 boxes of
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13, 16, 18

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Sabemos que podemos calcular el total de plumas amarillos, por medio de la media.

16 = (12 + 14 + 15 + 24 + x + y + z) / 7

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x + y + z = 47

sabemos que la mediana es el valor medio, y que ese 46 debe dividirse entre 3 valores porque son 3 cajas, entonces debemos buscar los números adecuados para el valor 15 esté en la mitad, es decir de cuarto.

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quedaría:

12

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15

dieciséis

18 años

24

Si recalculamos la media:

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8 0
2 years ago
Clark Heter is an industrial engineer at Lyons Products. He would like to determine whether there are more units produced on the
larisa [96]

Answer:

No, at the 0.05 significance level, the number of units produced on the night shift is not larger.

Step-by-step explanation:

We are given that the mean number of units produced by a sample of 54 day-shift workers was 345. The mean number of units produced by a sample of 60 night-shift workers was 351.

Assume the population standard deviation of the number of units produced on the day shift is 21 and 28 on the night shift.

Let \mu_1 = population mean number of units produced on the day shift

      \mu_2 = population mean number of units produced on the night shift

So, <u>Null Hypothesis</u>, H_0 : \mu_1-\mu_2\geq0  or  \mu_1\geq\mu_2    {means that the mean number of units produced on the night shift is same or lesser on the day shift}

<u>Alternate Hypothesis,</u> H_A : \mu_1-\mu_2  or  \mu_1    {means that the mean number of units produced on the night shift is larger}

The test statistics that will be used here is <u>Two-sample z test statistics</u> as we know about population standard deviations;

              T.S.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{\sqrt{\frac{\sigma_1^{2} }{n_1}+\frac{\sigma_2^{2} }{n_2} } }  ~ N(0,1)

where, \bar X_1 = sample mean number of units produced by a sample of 54 day-shift workers = 345

        \bar X_2 = sample mean number of units produced by a sample of 60 night-shift workers = 351

       \sigma_1  = population standard deviation of the number of units produced on the day shift = 21

        \sigma_2 = population standard deviation of the number of units produced on the day shift = 28

        n_1 = sample of day-shift workers = 54

        n_2 = sample of night-shift workers = 60

So, <em><u>test statistics</u></em>  =  \frac{(345-351)-(0)}{\sqrt{\frac{21^{2} }{54}+\frac{28^{2} }{60} } }

                              =  -1.302

Now at 0.05 significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is more than the critical value of z as -1.302 > -1.6449 so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the mean number of units produced on the night shift is same or lesser than those produced on the day shift.

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