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Ganezh [65]
2 years ago
11

The Leaning Tower of Pisa in Italy was built between 1173 and 1350. A. Write an equation in slope-intercept form for the yellow

line. Equation: y= b. The tower is 56 meters tall. How far off center is the top of the tower? The top of the tower is meters off center
Mathematics
1 answer:
mote1985 [20]2 years ago
5 0

Answer:

The answer is below

Step-by-step explanation:

From the image of the leaning tower of Pisa, we can see that it passes through the point (7.75, 0) and (10.75, 42).

a) The equation of a line in slope intercept form is given by y = mx + b, where m is the slope and b is the intercept. Also, the equation of line passing through

(x_1,y_1)\ and\ (x_2,y_2)\ is:\\\\y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)

Hence since it passes through  (7.75, 0) and (10.75, 42), the equation is:

y-0=\frac{42-0}{10.75-7.75} (x-7.75)\\\\y=14(x-7.75)\\\\y=14x-108.5

b) When the tower is 56 meters tall, i.e. y = 56, we need to find the value of x:

y = 14x - 108.5

56 = 14x - 108.5

56 + 108.5 = 14x

164.5=14x

x = 164.5/14

x = 11.75

When the tower is 56 meters tall, the top of the tower is 11.75 m off center

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Answer:

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F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa
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a. Parameterize C by

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\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt

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\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)

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