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irina1246 [14]
1 year ago
10

Will surveyed students at his school about whether they have ever gone snowboarding and whether they own a skateboard. He found

that 35 of the 99 students who own a skateboard have snowboarded. Also, there were 13 students who have snowboarded but do not own a skateboard, and 147 students who have never gone snowboarding and do not own a skateboard.

Mathematics
2 answers:
11111nata11111 [884]1 year ago
4 0
Given a data on the relationship between the number of students that have ever gone snowboarding and <span>the number of students that own a skateboard.</span>

Given from the survey that <span>35 of the 99 students who own a skateboard have snowboarded and there were 13 students who have snowboarded but do not own a skateboard, and 147 students who have never gone snowboarding and do not own a skateboard.

We represent the above information in a two</span> way frequency table.

                              Have Snowboarded         Never Snawboarded          Total
Skateboard                          35                                     64                          99

No Skateboard                    13                                     147                        160

Total                                     48                                     211                        259
sergey [27]1 year ago
4 0

Answer:

C (pic below)

Step-by-step explanation:

Just took the test!

Brianliest plz!

<em>Saffron</em>

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Tomtit [17]

Answer:

A. Hypotenuse-leg (HL) congruence.

HL, when you have 2 right triangles and their hypotenuses are congruent you are able to say HL

Step-by-step explanation:

We know that the hypotenuse-leg theorem states that if the hypotenuse and one leg of a right triangle are congruent to hypotenuse and corresponding leg of another right triangle, then the triangles are congruent.  

hypotenuse(AB) of △BDA equals to hypotenuse (CD) of △DBC.  

BDA and DBC share a common side DB.

Using Pythagorean theorem we will get,

CD^{2}=DB^{2}+BC^{2}...(1)  \\\\AB^{2}=DB^{2}+AD^{2}...(2)

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DB^{2}+BC^{2}=DB^{2}+AD^{2}

Upon subtracting DB^{2} from both sides of our equation we will get,

BC^{2}=AD^{2}\\\\BC=AD

<h3>Therefore, by HL congruence △BDA ≅ △DBC.</h3>
6 0
1 year ago
Read 2 more answers
Carmela mixes 3/4 kilogram of walnuts, 1/2 kilogram of almonds, and 1/4 kilogram of pecans together. She divides the mixed nuts
Evgesh-ka [11]

Amount of walnuts=\frac{3}{4} kg

Amount of almonds=\frac{1}{2} kg

Amount of pecans=\frac{1}{4} kg

Total amount=\frac{3}{4}+\frac{1}{2}+\frac{1}{4}

LCM is 4 so sum is = \frac{3+2+1}{4}=\frac{6}{4} =\frac{3}{2}

As given, Carmela divides the mixed nuts into 3/10 kilogram bags so number of bags will be:

\frac{\frac{3}{2}}{\frac{3}{10}}

= \frac{3}{2}\times\frac{10}{3} = 5

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2 years ago
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</span>Calculate the quantity one-half times the square of  divided by the value found in step 2, or 4.75. (1/2  * (3/4)^2) <span>÷ 4.75 = 0.06.
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Subtract the value found in step 3 from the value found in step 2, or 4.75.
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1 year ago
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If a conditional statement is “If the sun shines, people will be in good moods”, what is the statement “If the sun does not shin
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Answer:

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1 year ago
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Answer:

75 in coupons.

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her total income is 250 + 75 + 175 = 500.  

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8 0
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