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puteri [66]
2 years ago
10

When solving a system of equations, Jared found y = x + 10 for one equation and substituted x + 10 for y in the other equation.

Nicole found x = y – 10 for the same equation and substituted y – 10 for x in the other equation. Who is correct? Explain.
Mathematics
2 answers:
DedPeter [7]2 years ago
8 0

Answer:

Both Jared and Nicole are correct. You can solve for either variable and use the equivalent expression to create a one-variable equation. Then you can solve. Jared would have created a one-variable equation that can be used to solve for x, whereas Nicole would have created a one-variable equation that can be used to solve for y

Step-by-step explanation:

This is the sample answer that Ingenuity has offered.

myrzilka [38]2 years ago
5 0
Both are correct they just chose a different variable to solve for first. they will both get correct answers if they do the rest correctly.
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Answer:

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Step-by-step explanation:

Bruce's vector is <5cos(90-25), 5sin(90-25)> = <5cos(65), 5sin(65)> ≈ <2.1130913087, 4.53153893518>

The wind's vector is <3.5cos(270-60), 3.5sin(270-60)> = <3.5cos(210), 3.5sin(210)>  ≈ <−3.03108891325, −1.75>

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<−0.91799760455, 2.78153893518>

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A line extends from point T to point R. Point S is between points T and R. The space between T and S is labeled 3 x minus 4. The
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Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Triangle H N K is shown. Angle H N K is 90 degrees. The length of hypotenuse H K is n, the length of H N is 12, and the length o
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Answer:

13

Step-by-step explanation:

From the question, we are given a triangle HNK with an angle of 90°

The length of hypotenuse H K is n,

the length of HN is 12

the length of N K is 6.

From the above values, obtained in the question, we can see that this is a right angled triangle.

We are asked to find the length of the hypotenuse.

We can use Pythagoras Theorem of solve for this.

c² = a² + b²

where c = HK = n

a = NK = 6

b = HN = 12

c² = 6² + 12²

c² = 36 + 144

c² = 180

c = √180

c = 13.416407865

Approximately to the nearest whole number = 13

Therefore the value of HK = n = 13

We can also use Law of Cosines as given in the question to solve for this.

a² = b² + c² - 2ac × Cos A

where c = HK = n

a = NK = 6

b = HN = 12

Hence

c² = a² + b² - 2ab × Cos C

c = √ (a² + b² - 2ab × Cos C)

Where C = 90

c = √ 6² + 12² - 2 × 6 × 12 × Cos 90

c = 13.42

Approximately to the nearest whole number ≈ 13

Therefore the value of HK = n = 13

8 0
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