The answer is 64
- the side length of the square is 8 units
- area of square = a^2
- 8^2
- 64 :)
Answer:
1.5 feet
Step-by-step explanation:
Bob wants to plant a 7 foot by 10 foot garden.
Area =
square feet
He wants to make a uniform border of petunias around the outside and still have 28 square feet to plant tomatoes and roses in the middle.
Means we have to factor 28 in a way that the length and width is less than 10 and 7.
28 = 2 x 2 x 7
Means 4 feet can be width and 7 feet the length of the area where tomatoes need to be planted.
So, we have
feet less than outer garden means at each side
feet decreases.
Similarly, we have
feet less width and at each side it is 1.5 feet.
Therefore, the border of petunias will be 1.5 feet wide on all sides.
To find the decks area we subtract the pool from the total so we times 4 by 5 to get 20 subtracting that from 90 gives us 70 square yards and we then find the square root and get 8.36660026534076
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<u>Solution</u><u>:</u></h2>
We all know that,
- All animals have 2 eyes.
- All cows have 4 feet
- All hens have 2 feet
So, Let the no. of cows be x and chickens be y
According to question,
- Total number of eyes = 162
Framing equation,
⇛ Eyes of cows + Eyes of chickens = 162
⇛ 2x + 2y = 162
⇛ 2(x + y) = 162
⇛ x + y = 162/2 = 81 -----------(1)
According to question(Cond.-1)
- Total number of feet = 270
Framing equation,
⇛ Feet of cows + Feet of chickens = 270
⇛ 4x + 2y = 270
⇛ 2(2x + y) = 270
⇛ 2x + y = 135 ----------(2)
Subtracting eq.(1) from eq.(2),
⇛ 2x + y - (x + y) = 135 - 81
⇛ 2x + y - x - y = 54
⇛ x = 54
Putting value of x in eq.(1),
⇛ 54 + y = 81
⇛ y = 81 - 54
⇛ y = 27
⚘ So, Total number of animals,
- Number of cows = x = 54
- Number of chickens = y = 27
Hence, solved !
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