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Artemon [7]
1 year ago
11

If Bert had 3 cents more he would have twice as much as Georgia. If he had 4 cents less, he would have the same amount.

Mathematics
1 answer:
Mandarinka [93]1 year ago
8 0
2G=B+3
G=B-4

2(B-4)=B+3
2B-8=B+3
B=11

Bert has 11 cents
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Diane has a hospital appointment. When she arrives at the hospital, the car park is nearly full. There are a total of 534 car pa
nevsk [136]
Hiii

all you do is subtract...
534-476=58

58 spots are left.
6 0
1 year ago
2x-10/4=3x<br> −10<br> −1<br> 2<br> 11
evablogger [386]

Answer:

<h2>-1</h2>

Step-by-step explanation:

\dfrac{2x-10}{4}=3x\qquad\text{multiply both sides by 4}\\\\2x-10=12x\qquad\text{subtract}\ 2x\ \text{from both sides}\\\\-10=10x\qquad\text{divide both sides by 10}\\\\-1=x\to x=-1

6 0
2 years ago
Write an absolute value equation to satisfy the given solution set shown on a number line.
aivan3 [116]

Answer: IX - 4I ≤ 4

Step-by-step explanation:

In the numer line we can see that our possible values of x are in the range:

0 ≤ x ≤ 8

And we want to find an absolute value equation such that this set is the set of possible solutions.

An example can be:

IX - 4I ≤ 4

To construct this, we first find the midpoint M of our set, in this case is 4.

Then we write:

Ix - MI  ≤ IMI

Notice that i am using the minor and equal sign, this is because the black dots means that the values x = 0 and x = 8 are included, if the dots were empty dots, it would be an open set and we should use the <  > signs.

8 0
2 years ago
The endpoints of (line segment )AB are A(2, 2) and B(3, 8). (line segment ) AB is dilated by a scale factor of 3.5 with the orig
horrorfan [7]
The slope:
m = ( y2 - y1 ) / ( x2 - x1 ) = ( 8  2 ) / ( 3 - 2 ) = 6 / 1 
m = 6  ( we have the same slope for AB and A`B` )
AB = √[( 3 - 2 )² + ( 8 - 2 )²] = √37
A`B` = 3.5 √37 = 21.29 
5 0
1 year ago
Read 2 more answers
Announcements for 84 upcoming engineering conferences were randomly picked from a stack of IEEE Spectrum magazines. The mean len
Marina86 [1]

Answer:

Step-by-step explanation:

Hello!

You need to construct a 95% CI for the population mean of the length of engineering conferences.

The variable has a normal distribution.

The information given is:

n= 84

x[bar]= 3.94

δ= 1.28

The formula for the Confidence interval is:

x[bar]±Z_{1-\alpha/2}*(δ/n)

Lower bound(Lb): 3.698

Upper bound(Ub): 4.182

Error bound: (Ub - Lb)/2 = (4.182-3.698)/2 = 0.242

I hope it helps!

6 0
2 years ago
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