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SIZIF [17.4K]
2 years ago
14

Patricia is separating 16 soccer cards and 22 baseball cards into groups each group have the same number of cards madk and each

group only have one kind of sports card what is the greatest number of cards she can put in each group how many groups for each type of card will be
Mathematics
1 answer:
Rama09 [41]2 years ago
3 0
We have to find the Greatest Common Factor of 16 and 22.GCF ( 16, 22 ) = 2So the greatest number of cards she can put in each group is 2.16 : 2 = 822 : 2 = 11There will be 8 groups of soccer cards and 11 groups of baseball cards.

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Vince weighs 160 pounds and his friend nadir weighs 140 nadir calculated that his weight on another planet would be about 56lb a
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Vince would weigh 64 pounds
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2 years ago
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A summer camp cookout is planned for the campers and their families. There is room for 200 people. Each adult costs $4, and each
Sati [7]

Answer:

A.\\\\x+y\leq200\\\\4x+3y\leq750

Step-by-step explanation:

x - number of adults

y - number of campers

<em>The room for 200 people</em>: x + y ≤ 200

<em>Each adult costs $4, and each camper costs $3</em>: 4x and 3y

<em>A maximum budget of $750</em>: 4x + 3y ≤ 750

5 0
1 year ago
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Box A is 567 inches high, 678 inches wide, and 789 inches long. It has a maximum capacity of 1,200 marbles, Box B has three time
kotykmax [81]

Answer:

1701 high

2712 wide

789 long

= 4413

Step-by-step explanation:

3 0
1 year ago
If f Superscript negative 1 Baseline (x) = negative one-fifth x, what is f Superscript negative 1 Baseline (x) = one-fifth x?
Artyom0805 [142]

Answer:

  a different inverse function

Step-by-step explanation:

If f^{-1}(x)=-\frac{1}{5}x then f^{-1}(x)=\frac{1}{5}x is a different inverse function.

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The second (inverse) function is the first reflected over the y-axis.

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1 year ago
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Tim was given a large bag of sweets and ate one third of the sweets before stopping as he was feeling sick. The next day he ate
mars1129 [50]

Answer: In the beginning he was given 27 sweets.

Step-by-step explanation: The most logical thing to do is to solve it backwards, that is, from what he had at the end of the third day up till the beginning of the first day.

On the third day he ate one-third and had 8 sweets left over. To determine how many he started with on the third day, let the total on day three be called a. If one-third of a is eaten, then the left over which is two-thirds is 8. That is;

8/a = 2/3

By cross multiplication we now have

8 x 3 = 2a

24/2 = a

a = 12

Let the number of sweets he had on day two be called b. If he ate one-third of b and he had 12 left over, then the two-thirds left over is 12 and we now have;

12/b = 2/3

By cross multiplication we now have

12 x 3 = 2b

36 = 2b

36/2 = b

b = 18

Let the number of sweets he had on day one be called x. If he ate one-third of x and he had 18 left over, then the two-thirds left over is 18, and we now have;

18/x = 2/3

By cross multiplication we now have

18 x 3 = 2x

54 = 2x

x = 27

Therefore Tim was given 27 sweets at the beginning.

3 0
2 years ago
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