For a set population, does a parameter ever change?
Answer: For a set population, a parameter never change.
Because while computing the parameter each and every unit of the population is studied. Therefore, we can not expect a parameter to vary.
If there are three different samples of the same size from a set population, is it possible to get three different values for the same statistic?
Answer: Data from samples may vary from sample to sample, and so corresponding sample statistic may vary from sample to sample.
Because while calculating the sample statistic, we consider only the part of population. Every time we draw a sample from population, there is every possibility of getting different sample. Therefore, data from samples may vary from sample to sample and corresponding sample statistic may vary from sample to sample.
Answer:
![\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}3&1\\4&-2\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%261%5C%5C4%26-2%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The general matrix representation for this transformation would be:
![\left[\begin{array}{cc}x&y\end{array}\right] * A = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
As the matrix A should have the same amount of rows as columns in the firs matrix and the same amount of columns as the result matrix it should be a 2x2 matrix.
![\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
Solving the matrix product you have that the members of the result matrix are:
3x+4y = a*x + c*y
x - 2y = b*x + d*y
So the matrix A should be:
![\left[\begin{array}{cc}3&1\\4&-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%261%5C%5C4%26-2%5Cend%7Barray%7D%5Cright%5D)
Answer:
The Laplace transform of f(t) = 1 is given by
F(s) = (1/s) for all s>0
Step-by-step explanation:
Laplace transform of a function f(t) is given as
F(s) = ∫∞₀ f(t) e⁻ˢᵗ dt
Find the Laplace transform for when f(t) = 1
F(s) = ∫∞₀ 1.e⁻ˢᵗ dt
F(s) = ∫∞₀ e⁻ˢᵗ dt = (1/s) [-e⁻ˢᵗ]∞₀
= -(1/s) [1/eˢᵗ]∞₀
Note that e^(∞) = ∞
F(s) = -(1/s) [(1/∞) - (1/e⁰)]
Note that (1/∞) = 0
F(s) = -(1/s) [0 - 1] = -(1/s) (-1) = (1/s)
Hope this Helps!!!
Answer:
We are given eqaution: e=\frac{17}{20}d , where e the amount of euros and d is the value as U.S. Dollars.
We need to find number of euros for 1 U.S. Dollar.
Plugging d=1 in the given equation
We get
e=\frac{17}{20}(1)
On simplfying , we get
e=\frac{17}{20}
Dividing 17 by 20, we get 0.85.
Therefore, there would be 0.85 euro have the same value as 1 U.S. Dollar.
Read more on Brainly.com - brainly.com/question/11243826#readmore
Step-by-step explanation:
For finding the answer of such a question, we only multiply the function by the given value. so as for f(x)=34x2−1, The function g(x), a vertical stretch of f(x) by a factor of 8 is g(x) =8(34x2−1)
