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2 years ago

Given f(x) and g(x) = f(k⋅x), use the graph to determine the value of k.

Mathematics

2 answers:

zepelin [54]2 years ago

6 0

Answer:

The answer is 3

Step-by-step explanation:

I took the quiz

(Please give me brainiest)

yan [13]2 years ago

3 0

Answer:

The value of k is 3.

Step-by-step explanation:

The function f(x) passes through the points (0,4) and (-6,-2)

So the equation of the function is $\frac{y-4}{4-(-2)} = \frac{x-0}{0-(-6)}$

⇒ y = x + 4 ....... (1)

Again the function g(x) passes through the points (0,4) and (-2,-2).

Therefore, the equation of g(x) will be $\frac{y-4}{4-(-2)} =\frac{x-0}{0-(-2)}$

⇒ y = 3x + 4

Therefore, g(x) = 3x + 4 = f(3x) {from equation (1).

So, the value of k is 3. (Answer)

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The probability of contamination in batch 1 of a drug (event A) is 0.16, and the probability of contamination in batch 2 of the

VLD [36.1K]

We have:
Event A ⇒ P(A) = 0.16
Event B ⇒ P(B) = 0.09
Probability of event B given event A happening, P(B|A) = P(A∩B) / P(A) = 0.12

By the conditional probability, the probability of event A and event B happens together is given by:
P(B|A) = P(A∩B) ÷ P(A)
P(B|A) = P(A∩B) ÷ 0.16
0.12 = P(A∩B) ÷ 0.16
P(A∩B) = 0.12 × 0.16
P(A∩B) = 0.0192

When two events are independent, P(A) × P(B) = P(A∩B) so if P(A∩B) = 0.0192, then P(B) will be 0.0192 ÷ 0.16 = 0.12 (which take us back to P(B|A))

Since P(B|A) does not equal to P(B), event A and event B are not independent.

Answer: <span>Events A and B are not independent because P(B|A) ≠ P(B)</span>

4 0

2 years ago

A software engineer creates a LAN game where an 8 digit code made up of 1,2,3,4,5,6,7,8 has to be decided on, universal code . T

kotykmax [81]

Answer:

0.0143 = 1.43% probability that first 4 digits of the code are even numbers.

Step-by-step explanation:

Arrangements of n elements:

The number of possible arrangements of n elements is given by:

$A_{n} = n!$

Probability:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this question:

Desired outcomes:

First four digits are even(2, 4, 6 and 8 are even, so arrangements of 4 elements).

Last four digits are odd(1, 3, 5 and 7 are odd, so the last four elements are also arrangements of 4 elements). So

$D = 4!*4! = 24*24 = 576$

Total outcomes:

Arrangements of 8 digits. So

$T = A_{8} = 8! = 40320$

Probability:

$p = \frac{D}{T} = \frac{576}{40320} = 0.0143$

0.0143 = 1.43% probability that first 4 digits of the code are even numbers.

3 0

2 years ago

Kellan collected two sets of data and recorded them in the table.

tigry1 [53]

Answer:

Set 2 has a wider spread and has range of 27

Explanation:

We are given the below two sets of data:

Set 1 Set 2

17 81

13 70

18 94

24 68

21 95

Now, let's find the range of Set 1:

$Range=Maximum-Minimum$

$=24-13$

$=11$

Now, let's find the range of Set 2:

$Range= Maximum -Minimum$

$=95-68$

$=27$

Since, the Set 2 has more range, therefore, Set 2 has a wider spread and a range of 27

3 0

2 years ago

Read 2 more answers

A farmer plants corn in 1/4 of his field. He plants white corn in 3/5 of the corn

bija089 [108]

Answer:

$\frac{3}{20}$

Step-by-step explanation:

Fraction of the total that is for corn (TC - Total corn):

$TC=\frac{1}{4}$

fraction of the corn section that is for white corn (WC - white corn in the corn seccion):

$WC=\frac{3}{5}$

we need to find the fraction of the whole field that is for the white corn.

For this we need to find how much is $\frac{3}{5}$ out of the $\frac{1}{4}$ destinated to corn, and this will be the fraction of the total that is for white corn. We find this fraction by multiplying the fraction of corn ( $\frac{1}{4}$ ) by the fraction of white corn in the corn section ( $\frac{3}{5}$ ).