Answer:I am giving out 60 points if answer my question s
Step-by-step explanation:
Plz help
Answer:
{∅, {a}, {b}, {a,b}}
Step-by-step explanation:
The value of power of a set is generalized by using the formula,
Power of a set (P) = 2^n where n is the number of element in the set.
Given two distinct elements a and b say;
A = {a,b}
n(A) = 2 i.e the number of elements in the set is 2. Therefore the power of the set will be 2^n which gives 2^2 = 4.
P(A) = 4 means there are 4 subsets of the given set. Subsets are sets of elements that can be found in the set. The subsets of element A will be;
{∅, {a}, {b}, {a,b}} which gives 4 elements in total.
Note that empty set ∅ is always part of the subset of any given set
Answer:
Null Hypothesis: H_0: \mu_A =\mu _B or \mu_A -\mu _B=0
Alternate Hypothesis: H_1: \mu_A >\mu _B or \mu_A -\mu _B>0
Here to test Fertilizer A height is greater than Fertilizer B
Two Sample T Test:
t=\frac{X_1-X_2}{\sqrt{S_p^2(1/n_1+1/n_2)}}
Where S_p^2=\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2}
S_p^2=\frac{(14)0.25^2+(12)0.2^2}{15+13-2}= 0.0521154
t=\frac{12.92-12.63}{\sqrt{0.0521154(1/15+1/13)}}= 3.3524
P value for Test Statistic of P(3.3524,26) = 0.0012
df = n1+n2-2 = 26
Critical value of P : t_{0.025,26}=2.05553
We can conclude that Test statistic is significant. Sufficient evidence to prove that we can Reject Null hypothesis and can say Fertilizer A is greater than Fertilizer B.
Answer:
She should invest 6976.74 $ principal on daughter's 12th birthday.
Explanation:
We have I = prt, where I represents simple interest, p represents principal, r represents interest rate, and t represents time in years.
Here p + I = 12,000 $
So, I = 12000-p
Interest rate r = 12% =0.12
Number of years = 18 - 12 = 6 years.
Substituting
12000-p = p x 0.12 x 6
p + 0.72 p = 12000
1.72 p = 12000
p = 6976.74 $
So, she should invest 6976.74 $ principal on daughter's 12th birthday.
