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jenyasd209 [6]
2 years ago
7

In the Venn diagram, the blue circle represents when p is true, and the orange represents when q is true. A conjunction is true

in region . A disjunction is true in region(s) . A disjunction is false in region(s) .
Mathematics
2 answers:
spin [16.1K]2 years ago
8 0

Answer:

A conjunction is true in region:  B

A disjunction is true in region(s): A, B, and C

A disjunction is false in region(s):  D

Step-by-step explanation:  Edg...

Radda [10]2 years ago
3 0

Answer:

A conjunction is true in region  

✔ B  <--- Answer

A disjunction is true in region(s)  

✔ A, B, and C  <--- Answer

A disjunction is false in region(s)  

✔ D  <--- Answer

Step-by-step explanation:

I took the assaignment aswell

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Unlikely to have ????
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What is the first step to solve this equation : 11-3x=44
Zolol [24]

Answer:

Subtract 11 from both sides

Step-by-step explanation:

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2 years ago
Read 2 more answers
Explain why the following expression is false. |x| &lt; -4
levacccp [35]

Step-by-step explanation:

Whenever we put a negative number inside a modulus function it will give us the positive output. For example , |-3| = 3 , |-6|=6, |5|= 5 ,etc.

So a modulus function i.e. |x| is always greater than zero ( positive ) when x is any number except 0 and it is equal to zero when the value of x is 0.

So |x| can't be less than -4 as |x| is always positive . So the statement is false.

8 0
2 years ago
What is the equation of a line that is parallel to the line 2x + 5y = 10 and passes through the point (–5, 1)? Check all that ap
Bond [772]

So the right options are:

y=-\frac{2}{5}x-1

2x+5y = -5

y-1=-\frac{2}{5}(x+5)

Further explanation:

Given equation of line is:

2x+5y=10

We have to convert it into point-slope form

2x+5y=10\\5y=-2x+10\\Dividing\ both\ sides\ by\ 5\\y=-\frac{2}{5}x+\frac{10}{5}\\y=-\frac{2}{5}x+2

The co-efficient of x is the slope of the line

So,

m= -\frac{2}{5}

As the required line is parallel to given line, it will also have same slope.

Let m1 be the slope of required line

Then the line will be:

y=m_1x+b

Putting the value of slope

y=\frac{2}{5}x+b

Putting (-5,1) in the equation to find the value of b

1=-\frac{2}{5}(-5)+b\\1=2+b\\b=1-2\\b=-1

Putting the values of slope and b in equation

y=-\frac{2}{5}x-1

Multiplying the whole equation by 5 will give us:

5y = -2x-5

2x+5y = -5

Another form of equation of line is Point-slope form

y-y_1=m(x-x_1)

Putting the values of slope and point in the equation, we get

y-1=-\frac{2}{5}(x+5)

So the right options are:

y=-\frac{2}{5}x-1

2x+5y = -5

y-1=-\frac{2}{5}(x+5)

Keywords: Point-Slope form, Parallel lines

Learn more about point slope form at:

  • brainly.com/question/4464845
  • brainly.com/question/4522984

#LearnwithBrainly

4 0
2 years ago
Read 2 more answers
Prove tan3A= (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) ...?
aivan3 [116]
The solution to the problem is as follows:

<span>cos2A - cos4A = -2 sin(6A/2).sin(-2A/2) = +2 sin(3A).sinA
 
and
 
sin4A - sin2A = 2 cos(6A/2).sin(2A/2) = 2 cos(3A).sinA

Hence RHS = (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) = sin 3A / cos 3A = tan 3A = LHS
</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
5 0
2 years ago
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