She made 62 baskets by day 14. 4×13=52+10=62
Answer:
2801 boxes
Step-by-step explanation:
You have 1 red box
You have 7 blue boxes, so far 8 boxes
There are 49 total black boxes (7*7), making 57 total boxes
There are 49*7 = 343 yellow boxes, making 400 boxes
There are 343*7 = 2401 gold boxes, making for a total of 2801 boxes.
Answer:
a.) C(q) = -(1/4)*q^3 + 3q^2 - 12q + OH b.) $170
Step-by-step explanation:
(a) Marginal cost is defined as the decrease or increase in total production cost if output is increased by one more unit. Mathematically:
Marginal cost (MC) = change in total cost/change in quantity
Therefore, to derive the equation for total production cost, we need to integrate the equation of marginal cost with respect to quantity. Thus:
Total cost (C) = Integral [3(q-4)^2] dq = -(1/4)*(q-4)^3 + k
where k is a constant.
The overhead (OH) = C(0) = -(1/4)*(0-4)^3 + k = -16 + k
C(q) = -(1/4)*(q^3 - 12q^2 + 48q - 64) + k = -(1/4)*q^3 + 3q^2 - 12q -16 + k
Thus:
C(q) = -(1/4)*q^3 + 3q^2 - 12q + OH
(b) C(14) = -(1/4)*14^3 + 3*14^2 - 12*14 + 436 = -686 + 588 - 168 + 436 = $170
Answer:
Coordinates of Vertices of triangle ABC are A (-4,3) , B(4,4) and C(1,1).
As, DO is Dilation of Δ ABC by Scale factor of
.
Vertices of A' B'C' are

So, Image Δ A'B'C' will be smaller than the Pre image Δ ABC.
The two triangles will be congruent.
AO is Dilated by a factor of half , so A'O' will be half of AO.
So, correct Statements are
1. AB is parallel to A'B'.
2.DO,1/2(x, y) =
The distance from A' to the origin is half the distance from A to the origin.
Answer:
Cov(X, Y) =0.029.
Step-by-step explanation:
Given that :
The noise in a particular voltage signal has a constant mean of 0.9 V. that is μ = 0.9V ............(1)
Also, the two noise instances sampled τ seconds apart have a bivariate normal distribution with covariance.
0.04e–jτj/10 ............(2)
Having X and Y denoting the noise at times 3 s and 8 s, respectively, the difference of time = 8-3 = 5seconds.
That is, they are 5 seconds apart,
τ = 5 seconds..............(3)
Thus,
Cov(X, Y), for τ = 5seconds = 0.04e-5/10
= 0.04e-0.5 = 0.04/√e
= 0.04/1.6487
= 0.0292
Thus, Cov(X, Y) =0.029.