All categories

2 years ago

Arnav was 1.5 m tall. In the last couple of years, his height has increased by 20% percent.

Mathematics

2 answers:

Mekhanik [1.2K]2 years ago

6 0

Answer:

1.5 x 2= 3m its really just that easy.... it took me a while to learn this trick but it works for most things.

BlackZzzverrR [31]2 years ago

5 0

Answer: Arnav is 1.8m

Step-by-step explanation: I multiplied 1.5 by 0.20 and then added that answer to 1.5 and then I got 1.8

You might be interested in

after 24.0 days, 2.00 milligrams of an original 128.0 milligram sample remain. what is the half-life of the sample?

coldgirl [10]

(1/2)n = 0.015625
n log 0.5 = log 0.015625
n = log 0.5 / log 0.015625
n = 624 days / 6 half-lives = 4.00 days (the length of the half-life)

6 0

2 years ago

Consider the set A, of all integers from 1 to 10 inclusive (that means the 1 and the 10 are included in this set) Give a set B t

Mademuasel [1]

Answer:

$C^{I}$ = {2, 4, 10}

Step-by-step explanation:

A set is a collection of objects called elements. These element are refered to as members of the set.

Set A contains all integers from 1 to 10 inclusive;

A = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

A subset of a given set implies that every element of the subset are also elements of the given set. Set B is a subset of A;

B = {1, 3, 5, 6, 7, 8, 9}

Complement of a given set refers to elements not in the general set. Set C is the complement of B;

$C^{I}$ = {2, 4, 10}

3 0

2 years ago

Square $ABCD$ has area $200$. Point $E$ lies on side $\overline{BC}$. Points $F$ and $G$ are the midpoints of $\overline{AE}$ an

Charra [1.4K]

1. Consider square ABCD. You know that

$A_{ABCD}=AD^2=200,$

then

$AB=BC=CD=AD=10\sqrt{2}.$

2. Consider traiangle AED. F is mipoint of AE and G is midpoint of DE, then FG is midline of triangle AED. This means that

$FG=\dfrac{AD}{2}=\dfrac{10\sqrt{2} }{2}=5\sqrt{2}.$

3. Consider trapezoid BFGC. Its area is

$A_{BFGC}=\dfrac{FG+BC}{2}\cdot h,$ where h is the height of trapezoid and is equal to half of AB. Thus,

$A_{BFGC}=\dfrac{FG+BC}{2}\cdot \dfrac{AB}{2}=\dfrac{5\sqrt{2}+10\sqrt{2}}{2}\cdot \dfrac{10\sqrt{2}}{2}=75.$

$A_{BFGC}=A_{BFGE}+A_{EGC},\\A_{EGC}=A_{BFGC}-A_{BFGE}=75-34=41.$

5. Note that angles EGC and CGD are supplementary and

$\sin \angle CGD=\sin \angle EGC.$

Then

$A_{CGD}=\dfrac{1}{2}CG\cdot CD\cdot \sin \angle CGD=\dfrac{1}{2}CG\cdot EG\cdot \sin \angle CGE=A_{ACG}=41.$

Answer: $A_{CGD}=41.$

8 0

2 years ago

The number of bagels sold daily for two bakeries is shown in the table. Bakery A Bakery B 53 34 52 40 50 36 48 38 53 41 47 44 55

IrinaK [193]

You are given the number of bagels sold daily for bakeries A and B and are shown in the table above. Based on the above data, it is better to describe the centers of distribution in terms of the mean than the median. This is because all of the data from bakery A and B have values that are near the average and no data sample have possible outliers. For instance,

bakery A
mean (A) = [53 + 34 + 52 + 40 + 50 + 36 + 48 + 38]/8 = 43.88

Bakery B
mean (B) = [53 + 41 + 47 + 44 + 55 + 40 + 51 + 39]/8 = 46.25

Even if bakery A and B has the 38 and 39 as the lowest data respectively, they are still near the average data.

7 0

2 years ago

Negative 2 and two-thirds, negative 5 and one-third, negative 10 and two-thirds, negative 21 and one-third, negative 42 and two-

Naddika [18.5K]

Answer:

(D) f(x+1)=2f(x)

Step-by-step explanation:

The sequence is:

$-2\frac{2}{3}, -5\frac{1}{3}, -10\frac{2}{3}, -21\frac{1}{3}, -42\frac{2}{3}$