Answer:
The sample consisting of 64 data values would give a greater precision.
Step-by-step explanation:
The width of a (1 - <em>α</em>)% confidence interval for population mean μ is:

So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).
That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.
Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.
The two sample sizes are:
<em>n</em>₁ = 25
<em>n</em>₂ = 64
The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.
Width for n = 25:
Width for n = 64:
![\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]](https://tex.z-dn.net/?f=%5Ctext%7BWidth%7D%3D2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7B64%7D%7D%3D%5Cfrac%7B1%7D%7B8%7D%5Ccdot%20%5B2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Csigma%5D)
Thus, the sample consisting of 64 data values would give a greater precision
The distance between Adam and Liz is 7 meters. Sam ang Linda are 12 meters apart. Adam and Sam are 3 meters apart while Adam is 5 meters ahead of anyone. So, Sam finished first, then Adam, next is Liz, next is Rumi, last is Linda.
First, we need to find the area of the pond.
The formula for the area of a circle is: 3.14r^2
So, first of all, the radius is 10, and we need to square that, so 10 x 10 = 100.
There. Now, with the squared radius, we need to multiply that by pi.
100 x 3.14 = 314.
The area of the pond is 314 square meters.
Secondly, we need to find the number of frogs. If there are 2 frogs in each square meter, then 2 x 314 = 628.
There are 628 frogs in the pond.
Are there choices for this question? If not ,then the possible third variable that might most likely be responsible for the correlation between the number of concerts held in a city and number of local radio channels would be the number of radio channel listeners (since concerts and radio channels both are related to music).