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Alekssandra [29.7K]
2 years ago
5

Jeremy walks into a video arcade with a pocketful of quarters. He spends them at a rate of four every quarter hour until he runs

out. If the amount of of quarters Jeremy has is graphed overtime, which feature of the graph corresponds to Jeremy's initial amount of quarters, before he spends the first one ?
Answer Choices :
A. The y-intercept
B. The slope
C. The x-intercept
D. The minimum value
Mathematics
2 answers:
sdas [7]2 years ago
5 0
The answer is A as he has all of the quarters when he spends no time in the arcade
goldenfox [79]2 years ago
3 0

Answer: A. The y-intercept

Step-by-step explanation:

Given : The amount of quarters Jeremy has is graphed overtime.

Usually we represent the independent variable (time) by x and dependent variable (quarters) by y.

The y-intercept is the point in the graph where the x coordinate is zero.

When x-coordinate is zero then the graph is representing the initial value.

Hence, the feature of the graph corresponds to Jeremy's initial amount of quarters, before he spends the first one is the y-intercept .

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At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
2 years ago
Two different samples will be taken from the same population of test scores where the population mean and standard deviation are
Alenkinab [10]

Answer:

The sample consisting of 64 data values would give a greater precision.

Step-by-step explanation:

The width of a (1 - <em>α</em>)% confidence interval for population mean μ is:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{n}}

So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).

That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.

Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.

The two sample sizes are:

<em>n</em>₁ = 25

<em>n</em>₂ = 64

The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.

Width for n = 25:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{25}}=\frac{1}{5}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]        

Width for n = 64:

\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]

Thus, the sample consisting of 64 data values would give a greater precision

5 0
2 years ago
Read 2 more answers
The radius of the water well is 9 inches. Find the area of the water well
leva [86]

Answer:

A=254.34

Step-by-step explanation:

1. A=πr²

2. A=π(9)²

3. A=π(81)

4. A=3.14(81)

5. A=254.34

8 0
2 years ago
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How long is bob's journey from aberystwyth to shrewsbury
steposvetlana [31]

Answer: bob will take a while

Step-by-step explanation:

4 0
1 year ago
Jared is placing chairs around of rectangular stage. The stage is 10 feet long and 22 feet wide. He wants to put a chair at each
marishachu [46]
Hi there, I believe the answer is 20. Because, each corner is 4 chairs plus every two feet, equals 20. Hope this helps!
3 0
2 years ago
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