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Alekssandra [29.7K]
2 years ago
5

Jeremy walks into a video arcade with a pocketful of quarters. He spends them at a rate of four every quarter hour until he runs

out. If the amount of of quarters Jeremy has is graphed overtime, which feature of the graph corresponds to Jeremy's initial amount of quarters, before he spends the first one ?
Answer Choices :
A. The y-intercept
B. The slope
C. The x-intercept
D. The minimum value
Mathematics
2 answers:
sdas [7]2 years ago
5 0
The answer is A as he has all of the quarters when he spends no time in the arcade
goldenfox [79]2 years ago
3 0

Answer: A. The y-intercept

Step-by-step explanation:

Given : The amount of quarters Jeremy has is graphed overtime.

Usually we represent the independent variable (time) by x and dependent variable (quarters) by y.

The y-intercept is the point in the graph where the x coordinate is zero.

When x-coordinate is zero then the graph is representing the initial value.

Hence, the feature of the graph corresponds to Jeremy's initial amount of quarters, before he spends the first one is the y-intercept .

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The heights of the trees for sale at two nurseries are shown below. Heights of trees at Yard Works in feet : 7, 9, 7, 12, 5 Heig
Troyanec [42]

Answer:

The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

Step-by-step explanation:

1). Height of the trees at Yard Works are = 7,9,7,12,5 feet

So mean height of the trees = (7+9+7+12+5)÷5

                                               = 40÷5 =8 feet

Standard deviation of the trees at Yard works = ∑(║(height of the tree-mean height of the tree))║/(number of trees)

(height of the tree-mean height of the tree)= ║(7-8)║+║(9-8)║+║(7-8)║+║(12-8)║+║(5-8)║ = (1)+1+(1)+4+(3)= 10

Therefore standard deviation = (10)/(5) =2

2). In the same way mean height of the trees at Grow Station=(9+11+6+12+7)/5= 45/5 = 9

Now we will calculate the mean deviation of the tress at Grow Station

= ∑║(height of the tree-mean height of the tree)║/(number of trees)

= ║(9-9)║+║(11-9)║+║(6-9)║+║(12-9)║+║(7-9)║/(5)

= (0+2+3+3+2)/5

= 10/5 =2

Therefore The mean of tree heights at Yard Works is 8 feet and at Grow Station is 9 feet.The mean absolute deviation of the tree heights at both yards is 2.

                                                             

7 0
2 years ago
Read 2 more answers
High school students across the nation compete in a financial capability challenge each year by taking a National Financial Capa
zalisa [80]

Answer:

The students have to score 0.74 standard deviations above the mean to be publicly recognized.

Step-by-step explanation:

A random variable <em>X</em> is said to have a normal distribution with parameters <em>µ</em>    (mean) and <em>σ</em>² (variance).

If X \sim N (\mu, \sigma^{2}), then z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (<em>Z</em>) = 0 and Var (<em>Z</em>) = 1. That is, Z \sim N (0, 1).

The distribution of these <em>z</em>-scores is known as the standard normal distribution.

The <em>z</em>-score is a standardized form of the raw score, <em>X</em>. It is a numerical measurement of the relationship between a value (<em>X</em>) and the mean (<em>µ</em>) in terms of the standard deviation (<em>σ</em>). A <em>z</em>-score of -1 implies that the data value is 1 standard deviation below the mean. And a <em>z</em>-score of 1 implies that the data value is 1 standard deviation above the mean.

Let <em>X</em>  be defined as the scores of students at the National Financial Capability Challenge Exam.

It is provided that the students who score in the top 23% are recognized publicly for their achievement by the Department of the Treasury.

That is, P (X > x) = 0.23.

⇒ P(\frac{X-\mu}{\sigma}>\frac{x-\mu}{\sigma})=0.23

⇒

   P(Z>z)=0.23\\1-P(Z

The value of <em>z</em> for this probability value is:

<em>z</em> = 0.74.

*Use a <em>z</em>-table.

Thus, the students have to score 0.74 standard deviations above the mean to be publicly recognized.

8 0
2 years ago
The standard form of the equation of a parabola is x = y2 + 10y + 22. What is the vertex form of the equation?
iVinArrow [24]

From the conics form of the equation, shown above, I look at what's multiplied on the unsquaredpart and see that 4p = 4, so p = 1. Then the focus is one unit above the vertex, at (0, 1), and the directrix is the horizontal line y = –1, one unit below the vertex.

vertex: (0, 0); focus: (0, 1); axis of symmetry: x = 0; directrix: y = –1

Graph y2 + 10y + x + 25 = 0, and state the vertex, focus, axis of symmetry, and directrix.

Since the y is squared in this equation, rather than the x, then this is a "sideways" parabola. To graph, I'll do my T-chart backwards, picking y-values first and then finding the corresponding x-values for x = –y2 – 10y – 25:

To convert the equation into conics form and find the exact vertex, etc, I'll need to convert the equation to perfect-square form. In this case, the squared side is already a perfect square, so:

y2 + 10y + 25 = –x 
(y + 5)2 = –1(x – 0)

This tells me that 4p = –1, so p = –1/4. Since the parabola opens to the left, then the focus is 1/4 units to the left of the vertex. I can see from the equation above that the vertex is at (h, k) = (0, –5), so then the focus must be at (–1/4, –5). The parabola is sideways, so the axis of symmetry is, too. The directrix, being perpendicular to the axis of symmetry, is then vertical, and is 1/4 units to the right of the vertex. Putting this all together, I get:

vertex: (0, –5); focus: (–1/4, –5); axis of symmetry: y = –5; directrix: x = 1/4

Find the vertex and focus of y2 + 6y + 12x – 15 = 0

The y part is squared, so this is a sideways parabola. I'll get the y stuff by itself on one side of the equation, and then complete the square to convert this to conics form.

y2 + 6y – 15 = –12x 
y2 + 6y + 9 – 15 = –12x + 9 
(y + 3)2 – 15 = –12x + 9 
(y + 3)2 = –12x + 9 + 15 = –12x + 24 
(y + 3)2 = –12(x – 2) 
(y – (–3))2 = 4(–3)(x – 2)

Then the vertex is at (h, k) = (2, –3) and the value of p is –3. Since y is squared and p is negative, then this is a sideways parabola that opens to the left. This puts the focus 3 units to the left of the vertex.

vertex: (2, –3); focus: (–1, –3)

6 0
1 year ago
Is ΔWXZ ≅ ΔYZX? Why or why not? Yes, they are congruent by SAS. Yes, they are both right triangles. No, the triangles share side
gizmo_the_mogwai [7]
I will attached the picture of what you are talking about here. The answer for this problem is: Yes, that they are congruent by SAS. Meaning that the triangles are congruent if their included angles and any pair of corresponding sides are equal in both triangles. In this case, the sides are both 21 cm and this will make the angle equal for both triangles, so that is why they are congruent.

9 0
1 year ago
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Mrs.Schroeder, a school principal ,drove her own car for a class trip ,taking a different route . The principal's car can travel
dsp73

Answer:

the principal drove 384 miles

Step-by-step explanation:

12x32=384 miles

3 0
2 years ago
Read 2 more answers
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