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1 year ago

Solving radical equations How to solve radical equations

Mathematics

2 answers:

Dafna1 [17]1 year ago

8 0

Simplify radical expressions. If we combine these two things then we get the product property of radicals and the quotient property of radicals. These two properties tell us that the square root of a product equals the product of the square roots of the factors. no radicals appear in the denominator of a fraction.

lozanna [386]1 year ago

5 0

A radical equation is an equation in which a variable is under a radical. To solve a radical equation:

Isolate the radical expression involving the variable. If more than one radical expression involves the variable, then isolate one of them.

Raise both sides of the equation to the index of the radical.

If there is still a radical equation, repeat steps 1 and 2; otherwise, solve the resulting equation and check the answer in the original equation.

By raising both sides of an equation to a power, some solutions may have been introduced that do not make the original equation true. These solutions are called extraneous solutions.

Example 1

Solve equation.

Isolate the radical expression.

equation

Raise both sides to the index of the radical; in this case, square both sides.

equation

This quadratic equation now can be solved either by factoring or by applying the quadratic formula.

Applying the quadratic formula, equation

Now, check the results.

If equation, equation

If x = –5,

equation

The solution is equation or x = –5.

Example 2

Solve equation.

Isolate the radical expression.

equation

There is no solution, since equation cannot have a negative value.

Example 3

Solve equation.

Isolate one of the radical expressions.

equation

Raise both sides to the index of the radical; in this case, square both sides.

equation

This is still a radical equation. Isolate the radical expression.

equation

Raise both sides to the index of the radical; in this case, square both sides.

equation

This can be solved either by factoring or by applying the quadratic formula.

Applying the quadratic formula, equation

Check the solutions.

If x = 10, equation

So x = 10 is not a solution.

If x = 2, equation

The only solution is x = 2.

Example 4

Solve equation.

Isolate the radical involving the variable.

equation

Since radicals with odd indexes can have negative answers, this problem does have solutions. Raise both sides of the equation to the index of the radical; in this case, cube both sides.

equation

The check of the solution x = –15 is left to you.

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Mariulka [41]

Answer:

100% of the 2nd monthly payment go toward the repayment of principal.

Step-by-step explanation:

The loan taken is the Principal which is mentioned as $72,500 with interest at a nominal rate of 20%. Firstly, it is important to understand that nominal rate means <em>non-compounding </em>rate. Simply put will be a "<em>one-time charged" </em>rate on the loan. Since this is given as 20% of the Principal. It is calculated thus: $\frac{20}{100}$ × $\frac{72,500}{1}$ = $14,500. So the interest on the loan is $14,500. Added to the Principal the total amount to be paid back by the company becomes: $72,500 + $14,500 = $87,000. To pay back this amount at equal end-of-month installments in 1 year (12 months), we divide the total amount by 12. i.e $\frac{87000}{12}$ = $7250. This means, the monthly payment will be $7,250. Since the monthly payment pays only 10% of the initial principal $72,500. By the second month only 20% of the Principal would have been paid. So all of the monthly payment will go towards repaying the principal

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2 years ago

Ursula Works At A Print Shop. She Uses A Printer That Can Print 12 Pages Per Minute. Yesterday She Started Printing Flyers For A

BigorU [14]

Answer:

10:30 am.

Step-by-step explanation:

We have been given that Ursula uses a printer that can print 12 pages per minute.

Ursula started printing flyer for an order yesterday. Today at 8 am she continued working on the order, and by 9 a.m. she had 420 flyers for the order completed. The order was to print 1500 pages.

Let us find the number of pages left to print.

$\text{Number of the pages left to print}=1500-420$

$\text{Number of the pages left to print}=1080$

To find the time it will take to print 1080 pages we will divide number of pages left to print by number of pages printed per minute.

$\text{Time it will take to print 1080 pages}=\frac{1080\text{pages}}{\frac{\text{12 pages}}{\text{minute}}}}$

$\text{Time it will take to print 1080 pages}=\frac{1080\text{pages}}{12}\times \frac{\text{minute}}{\text{page}}}$

$\text{Time it will take to print 1080 pages}=90\text{ minutes}$

90 minutes will be 1.5 hours , so 1.5 hours after 9 am will be 10:30 am. Therefore, the job was finished at 10:30 am.

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1 year ago

james bought a cheeseburger, fries, and a drink for dinner. the cheeseburger was three times the price of the fries and the drin

nordsb [41]

The answer is $4.16 for each item

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1 year ago

19. Bella is putting down patches of sod

Fofino [41]

Answer:

The dimensions of the two different rectangular regions are;

1st Arrangement:

W = 4 yards and L = 5 yards or W = 5 yards and L = 4 yards

2nd Arrangement:

W = 2 yards and L = 10 yards or W = 10 yards and L = 2 yards

The perimeter of the two different rectangular regions are;

1st Arrangement:

P₁ = 18 yards

2nd Arrangement:

P₂ = 24 yards

Step-by-step explanation:

Bella is putting down patches of sod to start a new lawn.

She has 20 square yards of sod.

We are asked to provide the dimensions of two different rectangular regions that she can cover with the sod.

Recall that a rectangle has an area given by

Area = W*L

Where W is the width of the rectangle and and L is the length of the rectangle.

Since Bella has 20 square yards of sod,

20 = W*L

There are more than two such possible rectangular arrangements.

Out of them, two different possible arrangements are;

1st Arrangement:

20 = (4)*(5) = (5)*(4)

Width is 4 yards and length is 5 yards or width is 5 yards and length is 4 yards

2nd Arrangement:

20 = (2)*(10) = (10)*(2)

Width is 2 yards and length is 10 yards or width is 10 yards and length is 2 yards

Therefore, the dimensions of two different rectangular regions are;

1st Arrangement:

W = 4 yards and L = 5 yards or W = 5 yards and L = 4 yards

2nd Arrangement:

W = 2 yards and L = 10 yards or W = 10 yards and L = 2 yards

What is the perimeter of each region?

The perimeter of a rectangular shape is given by

P = 2(W + L)

Where W is the width of the rectangle and and L is the length of the rectangle.

The perimeter of the 1st arrangement is

P₁ = 2(4 + 5)

P₁ = 2(9)

P₁ = 18 yards

The perimeter of the 2nd arrangement is

P₂ = 2(2 + 10)

P₂ = 2(12)

P₂ = 24 yards

So the perimeter of the 1st arrangement is 18 yards and the perimeter of the 2nd arrangement is 24 yards.

Note:

Another possible arrangement is,

20 = (1)*(20) = (20)*(1)

Width is 1 yard and length is 20 yards or width is 20 yards and length is 1 yard.

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1 year ago

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igomit [66]

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2. Any straight line segment can be extended indefinitely in a straight line.

3. Given any straight line segment, a circle can be drawn having the segment as radius and one endpoint as center.

4. All right angles are congruent.

5. If two lines are drawn which intersect a third in such a way that the sum of the inner angles on one side is less than two right angles, then the two lines inevitably must intersect each other on that side if extended far enough. This postulate is equivalent to what is known as the parallel postulate.

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1 year ago