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inna [77]
2 years ago
11

The distance between two locations, A and B, is calculated using a third location C at a distance of 15 miles from location B. I

f ∠B = 105° and ∠C = 20°, what is the distance, to the nearest tenth of a mile, between locations A and B?
A) 42.4 miles
B) 35.9 miles
C) 6.3 miles
D) 5.3 miles
Mathematics
1 answer:
Alex Ar [27]2 years ago
7 0
First find ∠A: ∠A = 180°-(105°+20°) = 180°-125° = 55°
Make sure you know the Law of Sin (or Sin Law):
15/sin 55° = AB/sin 20°, then 15 / 0.81915 = AB/0.342
AB(0.81915) = 15(0.342)
AB(0.81915) = 5.13
AB = 5.13 : 0.81915 (ratio)
AB = 6.26 = 6.3 miles
Therefore, the distance between location A and location B is 6.3 miles.
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<h2>YES</h2>

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$163.54

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10 = 2W^2.H

H = 10 /2W^2

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Let C(w) = cost function

C(w) = 10(L.W) + 6(2.L.H + 2.W.H)

= 10(2W.W) + 6(2.2W.H + 2.W.H)

= 10(2W^2) + 6(4W.H + 2.W.H)

= 10(2W^2) + 6(4W*5/W^2 + 2.W*5/W^2)

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= 20W^2 + 6((10+20)/W)

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To find the minimum value, differentiate C with respect to w

C'(w) = 40W - 180/W^2

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0 = 40W - 180/W^2

40W = 180/W^2

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W^3 = 180/40

W^3 = 4.5

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C = 54.45 + 109.09

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