Adiya’s method is not correct. To form a perfect square trinomial, the constant must be isolated on one side of the equation. Also, the coefficient of the term with an exponent of 1 on the variable is used to find the constant in the perfect square trinomial. Adiya should first get the 20x term on the same side of the equation as x2. Then she would divide 20 by 2, square it, and add 100 to both sides.
Answer:
After one second, 130 ft
After two second , 60 ft
Step-by-step explanation:
Both boats are moving towards each other,
Speed of first boat = 40 ft/min.
Speed of second boat = 30 ft/min.
So, In one Second they must have covered a total distance of 40 + 30 ft
= 70 ft.
Total width of the lake = 200 ft
So, Distance remained between them after one second = 200 - 70 = 130 ft.
After two seconds , First boat will move my 80 ft and second one will move by 60 ft
So, distance between them will decrease by 140 ft.
Distance between the boats after two seconds = 60 ft.
Given my current rate = $129.00 per month.
Savings of 15% over your prices.
Therefore, saving = 15% of $129.00 = 0.15 × 129.00 =$19.35.
Adjusted rate = current rate - saving = 129 - 19.35 = $109.65
Therefore, We can rewrite above expression as :
My current rate is $129.00<u> </u><u>per month</u>." Representative: "We will match any competitive offer. Your adjusted rate will be <u>109.65 </u>dollars per month."
Answer:
-1.14
Step-by-step explanation:
The given information in statement is
mean=μ=69
standard deviation=σ=3.5
Let X be the Ishaan's exam score
X=65
The Z score can be computed as


z=-1.1429
z=-1.14 (rounded to two decimal places).
Thus, the computed z-score for Ishaan's exam grade is -1.14.
Answer:
The probability of Yarborough when you are randomly dealt 13 cards out of a well-shuffled deck of 52 card is 0.000547.
Step-by-step explanation:
The number of ways you can choose a set of 13 different cards from a deck of 52 cards is given by 52P13.
Hence the unordered sample space has 52P13 equally likely outcomes. The number of outcomes with no card above a nine is 32P13.
This leads to the same value for the desired probability of a Yarborough:
32P13 / 52P13 = 0.000547.