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defon
1 year ago
11

Manuela wants to have $26,000 in 18 months. About how much should she put into an 18 month CD that earns simple interest of 5.6%

a year calculated semiannually in order to reach her goal.
Mathematics
2 answers:
pentagon [3]1 year ago
5 0
Since it is simple interest, in 18 months it will earn 1.5*5.6 = 8.4%,

x + 0.084x = 26000

x = 2600/1.084 = $23,985.24
Leto [7]1 year ago
5 0

Answer:

Manuela should put $23,985.24 into an 18 month CD.

Step-by-step explanation:

Manuela wants to have $26,000 in 18 months CD that earns simple interest of 5.6% a year calculated semiannually.

Since it is simple interest so in 18 months (1.5 years)  it will earn = 5.6 × 1.5 = 8.4%.

Formula for Simple interest

A = P( 1 + rt)

A = amount ( 26,000 )

P = Principal  ( we have to find out )

r = Rate of interest in decimal 8.4% ( 0.084 )

t = time ( 1 )

Let the principal amount be x

Now we put the values in formula to find the value of x.

26,000 = x ( 1 + 0.084 × 1 )

26,000 = x ( 1.084 )

x = \frac{26000}{1.084}

x = 23,985.23985 rounded to 23,985.24

Manuela should put $23,985.24 into an 18 month CD.

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Which of the following is an equivalent form of the compound inequality −33 > −3x − 6 ≥ −6?
wolverine [178]

<u>ANSWER</u>

9\:   < x  \leqslant0

<u>EXPLANATION</u>

The given compound inequality is

- 33 \:  >  - 3x - 6 \geqslant  - 6

We need to simplify this inequality so that we can obtain x standing alone between the inequality signs.

We add 6 through out the inequality.

- 33  + 6\:  >  - 3x - 6 + 6 \geqslant  - 6 + 6

This simplifies to:

- 27\:  >  - 3x \geqslant  0

We now divide through by -3 and reverse the inequality sign.

\frac{- 27}{ - 3} \:   <   \frac{ - 3x}{ - 3}   \leqslant    \frac{0}{ - 3}

We now simplify to get:

9\:   < x  \leqslant    0

6 0
2 years ago
A triangle has side lengths of (1.3k+3.5m)(1.3k+3.5m) centimeters, (4.1k-1.6n)(4.1k−1.6n) centimeters, and (9.7n+4.4m)(9.7n+4.4m
Scorpion4ik [409]

Answer:

(5.4k+7.9m+8.1n) centimeters

Step-by-step explanation:

Given the side length of a triangle;

S1 = (1.3k+3.5m) cm

S2 = (4.1k-1.6n) cm

S3 = (9.7n+4.4m) cm

Perimeter of the triangle = S1+S2 + S3

Perimeter of the triangle = (1.3k+3.5m) + (4.1k-1.6n) + (9.7n+4.4m)

Collect the like terms;

Perimeter of the triangle = 1.3k+4.1k+3.5m+4.4m-1.6n+9.7n

Perimeter of the triangle = 5.4k+7.9m+8.1n

Hence the expression that represents the perimeter of the triangle is (5.4k+7.9m+8.1n) centimeters

5 0
1 year ago
Use inverse variation equation to fill the table.
ASHA 777 [7]

The correct answers to the question above includes:

a=.1
b=20.775
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7 0
2 years ago
Read 2 more answers
se the function to show that fx(0, 0) and fy(0, 0) both exist, but that f is not differentiable at (0, 0). f(x, y) = 9x2y x4 + y
alexandr1967 [171]

Answer:

It is proved that f_x, f_y exixts at (0,0) but not differentiable there.

Step-by-step explanation:

Given function is,

f(x,y)=\frac{9x^2y}{x^4+y^2}; (x,y)\neq (0,0)

  • To show exixtance of f_x(0,0), f_y(0,0) we take,

f_x(0,0)=\lim_{h\to 0}\frac{f(h+0,k+0)-f(0,0)}{h}=\lim_{h\to 0}\frac{\frac{9h^2k}{h^4+k^2}-0}{h}\\\therefore f_x(0,0)=\lim_{h\to 0}\frac{9hk}{h^4+k^2}=\lim_{h\to 0}\frac{9k}{h^3+\frac{k^2}{h}}=0    exists.

And,

f_y(0,0)=\lim_{k\to 0}\frac{f(h,k)-f(0,0)}{k}=\lim_{k\to 0}\frac{9h^2k}{k(h^4+k^2)}=\lim_{k\to 0}\frac{9h^2}{h^4+k^2}=\frac{9}{h^2}   exists.

  • To show f(x,y) is not differentiable at the origin cheaking continuity at origin be such that,

\lim_{(x,y)\to (0,0)}\frac{9x^2y}{x^4+y^2}=\lim_{x\to 0\\ y=mx^2}\frac{9x^2y}{x^4+y^2}=\frac{9x^2\times m x^2}{x^4+m^2x^4}=\frac{9m}{1+m^2}  where m is a variable.

which depends on various values of m, therefore limit does not exists. So f(x,y) is not continuous at (0,0). Hence it is not differentiable at (0,0).

4 0
2 years ago
The grade point average (GPA) of the students at Lakeview High School is normally distributed with a mean of 3.1 and a standard
Morgarella [4.7K]
Approximately 1718 have a score within that range.

We calculate the z-score for each end of this spectrum:

z = (X-μ)/σ = (2.5-3.1)/0.3 = -0.6/0.3 = -2

Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this z-score is 0.0228.

For the upper end:
z = (3.7-3.1)/0.3 = 0.6/0.3 = 2

Using a z-table, we see that the area to the left of, less than, this z-score is 0.9772.

The probability between these is given by subtracting these:
0.9772 - 0.0228 = 0.9544.

This means the proportion of people that should fall between these is 0.9544:
0.9544*1800 = 1717.92 ≈ 1718
4 0
1 year ago
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