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1 year ago

In a group of 90 students, 65 watch rugby, 71 play a sport and 15 do neither.

Mathematics

1 answer:

Dimas [21]1 year ago

4 0

Answer:

$\frac{14}{75}$ probability of selecting a student who plays a sport but does not watch rugby out of the people who play a sport.

Step-by-step explanation:

"Find the probability that a student chosen at random from those who play a sport does not watch rugby."

90-15= 75 students either play a sport OR watch rugby

65+71-75=

136-75=

61 people play a sport AND watches rugby

14 people play a sport and DOES NOT watch rugby

$\frac{14}{75}$ is the probability of selecting a student who plays a sport but does not watch rugby out of the people who play a sport.

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Find the absolute value of 3.1+(-6.3)

Sliva [168]

Answer:

3.2

Step-by-step explanation:

First, evalue what's inside of the absolute value:

3.1 + (-6.3) = -3.2

Now, since absolute value means the distance from the number to 0, the absolute value of -3.2 is the negation of -3.2:

|-3.2| = 3.2

7 0

1 year ago

The 3rd degree Taylor polynomial for cos(x) centered at a = π 2 is given by, cos(x) = − (x − π/2) + 1/6 (x − π/2)3 + R3(x). Usin

Otrada [13]

Answer:

The cosine of 86º is approximately 0.06976.

Step-by-step explanation:

The third degree Taylor polynomial for the cosine function centered at $a = \frac{\pi}{2}$ is:

$\cos x \approx -\left(x-\frac{\pi}{2} \right)+\frac{1}{6}\cdot \left(x-\frac{\pi}{2} \right)^{3}$

The value of 86º in radians is:

$86^{\circ} = \frac{86^{\circ}}{180^{\circ}}\times \pi$

$86^{\circ} = \frac{43}{90}\pi\,rad$

Then, the cosine of 86º is:

$\cos 86^{\circ} \approx -\left(\frac{43}{90}\pi-\frac{\pi}{2}\right)+\frac{1}{6}\cdot \left(\frac{43}{90}\pi-\frac{\pi}{2}\right)^{3}$

$\cos 86^{\circ} \approx 0.06976$

The cosine of 86º is approximately 0.06976.

8 0

2 years ago

Under what circumstances will the chi-square test for goodness of fit produce a large value for chi-square? Question options: a.

Whitepunk [10]

Answer:

a.when the sample proportions are much different than the hypothesized population proportions

Step-by-step explanation:

A chi-square test for goodness of fit is used to check the sample data were distributed according to claim or not.

If the chi-square test produces a large value of chi-square statistic then there is not a good fit between sample data and the null hypothesis. So, the sample proportions are much different than the hypothesized population proportions. Hence,Option (a) is correct.

If the goodness of fit produces a large value for chi-square then the sample means must not be close to the population mean. So, option (b) is incorrect.

4 0

2 years ago

If h(x)=3x-5 and g(x) =2x^2-7x, find (g•h)(x)

Murrr4er [49]

Answer:

The answer is 25.67and then you multiply by8 and get you 205.36

Step-by-step explanation:

4 0

1 year ago

Read 2 more answers

In a study of the progeny of rabbits, Fibonacci (ca. 1170-ca. 1240) encountered the sequence now bearing his name. The sequence

expeople1 [14]

The question in part c is not clear, nevertheless, part a and part b would be solved.

Answer:

a. The first twelve terms are:

1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144.

b. The first ten terms are:

1.000, 1.000, 1.500, 1.667, 1.600, 1.625, 1.615, 1.619, 1.618, 1.618.

Step-by-step explanation:

a. Given

an + 2 = an + an + 1

where a1 = 1 and a2 = 1.

a3 = a1 + a2

= 2

a4 = a2 + a3

= 3

a5 = a3 + a4

= 5

a6 = a5 + a4

= 8

a7 = a6 + a5

= 13

a8 = a7 + a6

= 21

a9 = a8 + a7

= 34

a10 = a9 + a8

= 55

a11 = a10 + a9

= 89

a12 = a11 + a10

= 144

The first twelve terms are:

1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144.

(b)

Given

bn = an+1/an

b1 = a2/a1

= 1/1 = 1.000

b2 = a3/a2

= 2/1 = 1.000

b3 = a4/a3

= 3/2 = 1.500

b4 = a5/a4

= 5/3 = 1.667

b5 = a6/a5

= 8/5 = 1.600

b6 = a7/a6

= 13/8 = 1.625

b7 = a8/a7

= 21/13 = 1.615

b8 = a9/a8

= 34/21 = 1.619

b9 = a10/a9

= 55/34 = 1.618

b10 = a11/a10

= 89/55 = 1.618

The first ten terms are:

1.000, 1.000, 1.500, 1.667, 1.600, 1.625, 1.615, 1.619, 1.618, 1.618.

6 0

1 year ago