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WARRIOR [948]
2 years ago
12

How many intersections are there of the graphs of the equations below? x + 5y = 6 3x + 30y = 36 none one two infinitely many Mar

k this and return Save and Exit
Mathematics
2 answers:
Step2247 [10]2 years ago
8 0

Answer:

this is inncorect the second option is false

Step-by-step explanation:

denpristay [2]2 years ago
5 0
I believe the answer would be the second option. The equations given above when graph would intersect only once with each other. They intersect at only point (0,6/5). These are the values of x and y that will agree to the equation. Two equations in a set will always intersect at only one point.
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1+4=5, 2+5=12, 3+6=21,8+11=
klemol [59]
The answer is 40 because once you have 21 your just adding 19 and then that makes it 40.
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2 years ago
A tractor costs $12,250 and depreciates in value by 6% per year. How much will the tractor be worth in 6 years?
GaryK [48]

Answer:

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
Todd is training for a marathon. The following histogram summarizes the number of kilometers that he ran each day. 00 0 11 1 22
olga2289 [7]

Answer:

The answer is 5/13

Step-by-step explanation:

I don't have a explanation but I do know this answer is correct because i has this question on my test.

5 0
2 years ago
Daisy measured the heights of 20 plants.
sergiy2304 [10]

Answer:

  • 30.5 cm

Step-by-step explanation:

<em>Refer to attached</em>

  • Height of plants (h) >> Frequency >> Midpoint >> Frequency x midpoint
  • 0 <h < 10 >>  1  >> 5 >> 5
  • 10 <h < 20 >> 4 >> 15 >>  60
  • 20 <h < 30 >> 7 >> 25 >> 175
  • 30 <h < 40 >> 2 >> 35 >> 70
  • 40 <h < 50 >> 3 >> 45 >> 135
  • 50 <h < 60 >> 3 >> 55 >> 165

Sum of frequencies = 20

Sum of frequency x midpoint product = 610

<u>Mean height </u>

  • 610/20 = 30.5 cm

5 0
2 years ago
Let a4+a8+a12+a16=224. Find the sum of first 19 term in sequence.
Tomtit [17]

Without knowing anything about the sequence, this is impossible to answer. But suppose the sequence is arithmetic, in which case each term differs by some constant k:

a_2=a_1+k

a_3=a_2+k=a_1+2k

a_4=a_3+k=a_1+3k

\ldots

a_n=a_{n-1}+k=a_1+(n-1)k

Then we can write

a_4+a_8+a_{12}+a_{16}=4a_1+36k=224\implies a_1+9k=56

and from the formula above, we see this means the 10th term in the sequence is a_{10}=56. But that's all the specific info we can gather about such an arithmetic sequence. If we set the first term to be some unknown a_1=a, then the sum of the first 19 terms in the sequence would be

\displaystyle\sum_{n=1}^{19}a_n=\sum_{n=1}^{19}\big(a+(n-1)k\big)=19a+k\sum_{n=1}^{18}n=19a+171k

If we knew one more term in the sequence, we could determine the value of k and derive the value of a (if the first term a_1 is not immediately given), and then go on to find an exact numeric value for the sum.

7 0
2 years ago
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