A school employs 30 teachers.how many will there be if there is a 10% reduction

Eli, Freda and Geoff were given £800 to share in the ratio of their ages.

algol13

First, we are going to find the sum of their age. To do that we are going to add the age of Eli, the age Freda, and the age of Geoff:
 $9+13+18=40$
The combined age of Eli, Freda, and Geoff is 40, so the denominator of each ratio will be 40.

Next, we are going to multiply the ratio between the age of the person and their combined age by £800:
For Eli: $\frac{9}{40} *800=180$
For Freda: $\frac{13}{40} *800=260$
For Geoff: $\frac{18}{40} *800=360$

We can conclude that Eli will get £180, Freda will get £260, and Geoff will get £360.

4 0

2 years ago

What is the equation of the translated function, g(x), if f(x) = x2?

Eddi Din [679]

All of these would be translated versions of f(x).

A translated version is simply one in which the base equation is used and then moved. Each of these equations are quadratics with a starting term of x^2. All of them move up and down or side to side in some way and direction, but all of them would be translated versions of that graph.

6 0

2 years ago

Las personas que venden computadoras en una tienda local ganan $100 en comisión por computadora por las primeras 5 computadoras

Flauer [41]

La respuesta es D. $1,050

4 0

2 years ago

The volume of clay used to build a cylindrical pillar with a height of 9 centimeters is 324π cubic centimeters. The area of the

stealth61 [152]

Area=height times base (for some prisms including cylinders)
vcylinder=hpir²
h=height
therefor pir²=base area
vcylinder=height times aeraofbase

given
h=9
v=324pi
324pi=9(basearea)
divide both sides by 9
36pi=areabase

the area of te base is 36pi square cm (put 36 in the blank since th pi is alredy there)

3 0

2 years ago

Read 2 more answers

There are 360 people in my school. 15 take calculus, physics, and chemistry, and 15 don't take any of them. 180 take calculus. T

lesantik [10]

Answer:

150 students take physics.

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the students that take calculus.

-The set B represents the students that take physics

-The set C represents the students that take chemistry.

-The set D represents the students that do not take any of them.

We have that:

$A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)$

In which a is the number of students that take only calculus, $A \cap B$ is the number of students that take both calculus and physics, $A \cap C$ is the number of students that take both calculus and chemistry and $A \cap B \cap C$ is the number of students that take calculus, physics and chemistry.

By the same logic, we have:

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

This diagram has the following subsets:

$a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C), D$

There are 360 people in my school. This means that:

$a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) + D = 360$

The problem states that:

15 take calculus, physics, and chemistry, so:

$A \cap B \cap C = 15$

15 don't take any of them, so:

$D = 15$

75 take both calculus and chemistry, so:

$A \cap C = 75$

75 take both physics and chemistry, so:

$B \cap C = 75$

30 take both physics and calculus, so:

$A \cap B = 30$

Solution:

The problem states that 180 take calculus. So

$a + (A \cap B) + (A \cap C) + (A \cap B \cap C) = 180$

$a + 30 + 75 + 15 = 180$

$a = 180 - 120$

$a = 60$

Twice as many students take chemistry as take physics:

It means that: $C = 2B$

$B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)$

$B = b + 75 + 30 + 15$

$B = b + 120$

-------------------------------

$C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)$

$C = c + 75 + 75 + 15$

$C = c + 165$

----------------------------------

Our interest is the number of student that take physics. We have to find B. For this we need to find b. We can write c as a function o b, and then replacing it in the equations that sums all the subsets.

$C = 2B$

$c + 165 = 2(b+120)$