For this case we have the following equation:

From here, we must substitute ordered pairs of the form:
(x, y)
If the ordered pair satisfies the equation, then it belongs to the line.
We have then:
For (8, 5):
We substitute the following values:

We observe that the equation is not satisfied and therefore, this point does not belong to the line.
Since one of the points does not belong to the line, then the equation is not a good model.
Answer:
It is not a good model. One of the points does not belong to the line.
The solution to the problem is as follows:
We have 2+.8(2) + .8(.8(2)) + .8(.8(.8(2))) + ... =
2( .8^0 + .8^1 + .8^2 + .8^3 + ... ) =
2(.8^n -1) / (.8-1) . As n-->infinity, .8^n-->0 giving us
<span>2(-1)/(-.2) = 2(5) = 10 meters.
</span>
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Answer:
0.63
Step-by-step explanation:
To get the relative frequency of students with red hair, we need to find the relative frequency of students with red hair from the students with gray eyes.
Since we already know that the total number of students with gray eyes is 35 and the number of red hair students with gray eye is 22
The formula we will use to calculate the relative frequency will be
The relative frequency of students with red hair = Total students of red hair with gray eyes divide by total number of gray eye students
22 ÷ 35 = 0.628 ≅ 0.63
She would be able to download 49 at this rate.
Because 5/35 =7/n which would then =245/5 which equals 49