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alina1380 [7]
2 years ago
9

Steffen graphed two lines in order to find the solution to a given system of equations. What is the solution?

Mathematics
2 answers:
Marysya12 [62]2 years ago
8 0

I know you are but what im i

Step-by-step explanation:

Pavlova-9 [17]2 years ago
7 0

check the picture below.

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The table shows the number of candies packed by Machine C. The equation shows the number of candies packed by Machine D. In both
Rashid [163]

Machine C makes 75 candies per minute.

Machine D makes 130 candies per minute.

Difference is 55


55 * 11 minutes = 605 candies.

4 0
2 years ago
Read 2 more answers
Chelsea has 11 times as many art brushes as Monique. If they have 60 art brushes altogether, how many brushes does Chelsea have?
notsponge [240]
Let Monique's number of art brushes be m.
Then, since Chelsea has <span>11 times as many art brushes as Monique, Chelsea has 11m brushes.

Together they have 60 art brushes, so we write the equation:

                                              m+11m=60.

This means that 12m=60, dividing both sides of the equation by 12 we get m=5.

Chelsea has 11m=11*5=55 brushes.

Answer: 55</span>
7 0
2 years ago
The grocery store is having a sale on frozen vegetables. 4 bags are being sold for $11.96. At this rate what is the cost of: 9 b
Alexandra [31]

Answer:

$26.91

Step-by-step explanation:

11.96 divided 4 = 2.99

2.99 x 9 = $26.91

4 0
2 years ago
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Solve: the quantity 3x minus 15 divided by 2 = 4x
Anon25 [30]

Answer:

x=-3

Step-by-step explanation:

(3x-15)/2 = 4x

Multiply each side by 2

(3x-15)/2 *2= 4x*2

3x-15 = 8x

Subtract 3x from each side

3x-15-3x = 8x-3x

-15 = 5x

Divide each side by 5

-15/5 = 5x/5

-3 =x

5 0
2 years ago
A length is measured as 21cm correct to 2 significant figures. what is the upper bound for the length?​
Leno4ka [110]

the upper bound for the length is  21.5  cm .

<u>Step-by-step explanation:</u>

Lower and Upper Bounds

  • The lower bound is the smallest value that will round up to the approximate value.
  • The upper bound is the smallest value that will round up to the next approximate value.

Ex:- a mass of 70 kg, rounded to the nearest 10 kg, The upper bound is 75 kg, because 75 kg is the smallest mass that would round up to 80kg.

Here , A length is measured as 21cm correct to 2 significant figures. We need to find what is the upper bound for the length . let's find out:

As discussed above , upper bound for any number will be the smallest value in decimals which will round up to next integer value . So , for 21 :

⇒ 21.5  cm

21.5 cm on rounding off will give 22 cm . So , the upper bound for the length is  21.5  cm .

7 0
2 years ago
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