Each year at a college, there is a tradition of having a hoop rolling competition.

Sue’s Corner Market has a markup of 60% on bottled water. If the market sells a bottle of water for $2, find the original amount

lakkis [162]

Markup is the amount added to the cost price of goods to cover overhead and profit.

Sue’s Corner Market has a markup of 60% on bottled water.

Let us say original price was $x.

Now price after markup is $2.

So we can make an equation like:

original price + markup price = price after markup

x + 60% of x =2

$x + 0.6x =2$

$1.6x =2$

dividing both sides by 1.6

x= 1.25

So original price was 1.25 dollars.

5 0

2 years ago

Read 2 more answers

Laurissa rolls two number cubes, each with the numbers 1 through 6. Laurissa adds the numbers that appear in the roll. Which two

defon

Answer:

Let's analyze the possible sums of both dices, i will use the notation:

Dice1 + Dice 2 = sum.

also remember that we have 2 dices, with 6 options each.

So the total number of combinations is 6*6 = 36

we have 36 possible outcomes.

I will start at the extremes, the minimum that we can sum is 2, and the maximum is 12, then:

We can have 2 if:

1 + 1 = 2

only one permutation.

and 12 if:

6 + 6 = 12

Again, only one permutation.

so 2 and 12 have the same chance (1 out of 36)

now, to have 3 we can have:

2 + 1 = 3

or

1 + 2 = 3.

and to have 11

5 + 6 = 11

6 + 5 = 11

Again, 3 and 11 have the same probability (2 out of 36 options)

And now we can see a pattern.

4 and 10 will have the same chance.

5 and 9 will have the same chance

6 and 8 will have the same chance

7 is the only number that has an unique chance (and it has the largest one)

3 0

2 years ago

An astronaut on the moon throws a baseball upward. the astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is

marta [7]

Answer:

Step-by-step explanation:

The position function is

$s(t)=-2.7t^2+50t+6.5$ and if we are looking for the time(s) that the ball is 10 feet above the surface of the moon, we sub in a 10 for s(t) and solve for t:

$10=-2.7t^2+50t+6.5$ and

$0=-2.7t^2+50t-3.5$ and factor that however you are currently factoring quadratics in class to get

t = .07 sec and t = 18.45 sec

There are 2 times that the ball passes 10 feet above the surface of the moon, once going up (.07 sec) and then again coming down (18.45 sec).

For part B, we are looking for the time that the ball lands on the surface of the moon. Set the height equal to 0 because the height of something ON the ground is 0:

$0=-2.7t^2+50t+6.5$ and factor that to get

t = -.129 sec and t = 18.65 sec

Since time can NEVER be negative, we know that it takes 18.65 seconds after launch for the ball to land on the surface of the moon.

4 0

1 year ago

A-B=18 A:B is equivalent to 11:5

densk [106]

One way is to use brute force (find bigger equivalent ratios and add them)
11:5
to make them bigger, we multiply both by the same number
11:5
11+5=16 nope
11:5 times 5 to both=55:25
add
55+25=80
we can just add the numbers before multiplying and then multiply after

11+5=16
16 times what=18
divide both sides by 16
1.125=what
we need to multiply each by 1.125
11:5 times 1.125 to both =12.375 : 5.625
12.375+5.625=18

a=12.375
b=5.625

Hope this helps :)

8 0

2 years ago

Read 2 more answers

In a completely randomized experimental design involving three assembly methods, 30 employees were randomly selected and 10 were

AnnZ [28]

Answer:

$F = \frac{MSR}{MSE} =\frac{45.89}{6.27}=7.32$

So then the best option is:

a. 7.32

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have $3$ groups and on each group from $j=1,\dots,10$ we have $10$ individuals on each group we can define the following formulas of variation: