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Otrada [13]
2 years ago
11

Laurissa rolls two number cubes, each with the numbers 1 through 6. Laurissa adds the numbers that appear in the roll. Which two

sums have an equal chance of occurring?
Mathematics
1 answer:
defon2 years ago
3 0

Answer:

Let's analyze the possible sums of both dices, i will use the notation:

Dice1 + Dice 2 = sum.

also remember that we have 2 dices, with 6 options each.

So the total number of combinations is 6*6 = 36

we have 36 possible outcomes.

I will start at the extremes, the minimum that we can sum is 2, and the maximum is 12, then:

We can have 2 if:

1 + 1 = 2

only one permutation.

and 12 if:

6 + 6 = 12

Again, only one permutation.

so 2 and 12 have the same chance (1 out of 36)

now, to have 3 we can have:

2 + 1 = 3

or

1 + 2 = 3.

and to have 11

5 + 6 = 11

6 + 5 = 11

Again, 3 and 11 have the same probability (2 out of 36 options)

And now we can see a pattern.

4 and 10 will have the same chance.

5 and 9 will have the same chance

6 and 8 will have the same chance

7 is the only number that has an unique chance (and it has the largest one)

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Answer:

1,100 dollars divided by 5 friends is 220 dollars so each friend would have to pay 220 dollars

Step-by-step explanation:


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Nicole wants to know the height of a snow sculpture but it is too tall to measure. Nicole measured the shadow of the snow sculpt
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What are the possible numbers of positive real, negative real, and complex zeros of f(x) = −7x4 − 12x3 + 9x2 − 17x + 3?
madreJ [45]
Now, recall Descartes Rule of Signs.  Check the picture below.

the +x part, gives us the positive Real zeros, and it depends on how many times the sign changes from term to term, notice in the picture, it changed 3 times, so the positive real ones are 3, or 3-2, namely 1, so 3 or 1.

the negative real ones, come from using -x as the argument on f(x), and as you can see in the picture, there was only 1 sign change, meaning the negative real zeros are only 1.

since, based on the fundamental theorem of algebra the polynomial has 4 roots at most then,

3 positive real ones, and 1 negative real one, no complex ones

or

1 positive real one, and 1 negative real one, and 2 complex ones

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8 0
2 years ago
To a survey of 290 newspaper reader, 181
astra-53 [7]

Question:

To a survey of 290 newspaper readers, 181 of them read the Daily Times, 142 Read the Guardian 117 read punch and each reads at least one of the three papers if 75 read the Daily Times, and the Guardian, 60 read the Daily Times and punch, and 54 read the Guardian and punch : Draw a Venn diagram to illustrate this information How many readers read All three papers ,Exactly two of the papers The Guardian alone?

Answer:

39 read all three news papers,72 Exactly two Papers & 52 reads  Guardian Alone

Step-by-step explanation:

We have given, A survey of 290 newspaper readers.

Who read the Daily times A=181  

Who read the Guardian times B=142  

Who read the punch C=117

Who read Daily Times and the Guardian A\cap B= 75

Who read Daily Times and the punch A\cap C=60

Who read Guardian and punch B\cap C=54

To find :

How many readers read All three papers, Exactly two of the papers The Guardian alone?

Solution :

Readers read all three papers is A\cap B\cap C

Total survey is given by,

Total = A+B + C- A\cap B- A\cap C - B\cap C+ A\cap B\cap C

290 = 181 + 142 + 117 - 75 -60 - 54 +A\cap B\cap C

290 =251+A\cap B\cap C

290-251=A\cap B\cap C

A\cap B\cap C=39

So, number of readers who read all three papers is 39.

Exactly two of the papers = 36 + 21 + 15 = 72

Guardian Alone = 52

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