Question

12x+7<−11 AND5x−8≥4012

Answer 1

Answer:

No solution

Step-by-step explanation:

Given: $12x+7$ and  $5x-8\geq 40$

Solve both inequality separately.

$12x+7$              Subtraction property of inequality

$12x$

$12x$

$x$

$x$

and

$5x-8\geq 40$               Addition property of inequality

$5x\geq 40+8$

$5x\geq 48$

$x\geq \dfrac{48}{5}$

Hence, the solution of the compound inequality intersection of both solutions.

Please find attachment for number line solution.

No solution

Answer 2

Answer:

No Solution

Step-by-step explanation: