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CaHeK987 [17]
1 year ago
12

Find the quotient 4^10/4^2

Mathematics
1 answer:
Tanya [424]1 year ago
3 0

Answer:65536

4^10/4^2

4*4=16

4*4*4*4*4*4*4*4*4*4=1048576

1048576/16=65536

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16.5 has the same ratio
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Rachel has completed 2/3 of her shift; Jose has completed 1/6 of his shift; Damon has finished 4/5 of his shift; and Stacy has 6
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Answer:

C. Stacy

Step-by-step explanation:

One way to compare is to convert all the fractions into decimals

    Rachel works 2/3 of her shift: Approximately= 0.667

    Jose works 1/6: approx. = 0.1667

    Damon works 4/5= 0.80

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Now this makes it much easier to compare

And since 0.85714 (Stacy's shift) is the largest number, Stacy has completed the largest portion of her shift

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2 years ago
The state of south dakota has a population of about 814,000 people. Find the population density in people per square miles if th
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Remark

Not many per square mile. Sounds like an ideal place to live.

Step One

Find the number of Square Miles.

Area = Height * Width

Area = 380 * 200

Area = 76,000 square miles.

Step Two

Find the Density

<u>Formula</u>

Density = Population / Square Miles

Population = 814,000 people

Square miles = 76000

Solve

Density = 814000/76000 = 10.7 people per square mile.

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Isn't that incredible. It means if all the Area of South Dakota were given to the people living there, each family of 4 would get roughly 1/2 a square mile.

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2 years ago
Most US adults have social ties with a large number of people, including friends, family, co-workers, and other acquaintances. I
xxTIMURxx [149]

Answer:

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

p_v =2*P(t_{(1699)}>1.971)=0.049  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation  

\bar X=669 represent the sample mean

s=732 represent the sample standard deviation

n=1700 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0. represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:  

Null hypothesis:\mu = 634  

Alternative hypothesis:\mu \neq 634  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(1699)}>1.971)=0.049  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

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