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Vilka [71]
1 year ago
5

The function y=7500(1.08)t represents the value y of an investment after t years. What is the value of the investment after 6 ye

ars?
Mathematics
1 answer:
boyakko [2]1 year ago
4 0

Answer:

The answer is 48600, but I'm not entirely sure if it correct.

From what I know, if I were to see ¨y=7500(1.08)t¨, we could have to substitute the t with the number of years. Looking like this, ¨y=7500(1.08) x 6¨.

The reason I don know if my answer is correct or not since I don know if you have the t next to 1.08 to represent that or to simply multiply the property of it with 6 (the number of years).

So I tried...

Step-by-step explanation:


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A motorcycle has an initial speed of u m/s. It accelerates to a speed of 1.2u in 10 seconds. The motorcycle then travels at a co
kolbaska11 [484]

Answer:

Step-by-step explanation:

A motorcycle has an initial speed of u m/s. It accelerates to a speed of 1.2u in 10 seconds

V = U + at

1.2u  = u  + a*10

=> a = 0.02u

S= ut + (1/2)at²

Distance in 1st 10 secs

S = u(10) + (1/2)(0.02)(10)²

=> S = 10u + u

=>  S = 11u  m

Constant speed 1.2u for 15 secs

S = 1.2u * 15

=> S = 18u m

Total Distance Covered d  = 11u + 18u = 29u  m

6 0
2 years ago
The area of a small pond is 78.5 yds. What is the diameter of the pond?
Zolol [24]

Answer:

Diameter of pound = 10 yd

Step-by-step explanation:

Given area of circular pond = 78.5 square yd

To find the diameter of the pond.

Solution:

The pond being circular in shape, the area of pond can be given as:

⇒ \pi\ r^2

where r represents radius of the pond.

Thus, we have:

⇒ \pi\ r^2=78.5

Using \pi=3.14

⇒ 3.14r^2=78.5

Solving for r

Dividing both sides by 3.14

⇒ \frac{3.14r^2}{3.14}=\frac{78.5}{3.14}

⇒ r^2=25

Taking square root both sides.

⇒ \sqrt{r^2}=\sqrt{25}

⇒ r=\pm5

So, radius = 5 yd, as distances are always positive.

Diameter = 2\times radius=2\times 5\ yd= 10\ yd

Thus, diameter of pound = 10 yd

7 0
2 years ago
In the figure below, \overline{AD} AD start overline, A, D, end overline and \overline{BE} BE start overline, B, E, end overline
VLD [36.1K]

Answer:

<u>The measure of the arc CD = 64°</u>

Step-by-step explanation:

It is required to find the measure of the arc CD in degrees.

So, as shown at the graph

BE and AD are are diameters of circle P

And ∠APE is a right angle ⇒ ∠APE = 90°

So, BE⊥AD

And so, ∠BPE = 90° ⇒(1)

But it is given: ∠BPE = (33k-9)° ⇒(2)

From (1) and (2)

∴ 33k - 9 = 90

∴ 33k = 90 + 9 = 99

∴ k = 99/33 = 3

The measure of the arc CD = ∠CPD = 20k + 4

By substitution with k

<u>∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°</u>

6 0
1 year ago
The vertices of △ DEF are D (2, 5), E (6, 3), and F (4, 0). Translate △ DEF using the given vector. Graph △ DEF and its image. T
jeyben [28]

Answer:

The image coordinates are D'(8, 5), E'(12, 3) and F'(10,0)

Step-by-step explanation:

Given the vertices of △ DEF are D (2, 5), E (6, 3), and F (4, 0). We have to translate the triangle using the vector (6, 0)

Now, translation by vector (6, 0)

D (2, 5)=D'(2+6, 5+0)=D'(8, 5)

E (6, 3)=E'(6+6, 3+0)=E'(12, 3)

F (4, 0)=F'(4+6, 0+0)=F'(10,0)

Now, we have to label the coordinate of the triangle or to get image of triangle after translation.

Hence, The image coordinates are D'(8, 5), E'(12, 3) and F'(10,0)

7 0
2 years ago
In triangle ABC segment DE is parallel to the side AC. (The endpoints of segment DE lie on the sides AB and BC respectively).
ivanzaharov [21]

Answer:

6 dm

Step-by-step explanation:

Triangle DBE is similar to triangle ABC, so their side lengths are proportional.

DE/AC = DB/AB

The length of DB can be found from ...

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DB = AB -AD = (15 -10) dm = 5 dm

So, we can fill in the proportion:

DE/(18 dm) = (5 dm)/(15 dm)

DE = (18 dm)·(1/3) . . . . . . . . . . simplify, multiply by 18 dm

DE = 6 dm

_____

It can be helpful to draw and label a figure.

5 0
1 year ago
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