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garik1379 [7]
2 years ago
9

Sofia is working two summer jobs, making $12 per hour babysitting and making $8 per hour clearing tables. In a given week, she c

an work a maximum of 17 total hours and must earn a minimum of $180. If Sofia worked 14 hours babysitting, determine all possible values for the number of whole hours clearing tables that she must work to meet her requirements. Your answer should be a comma separated list of values. If there are no possible solutions, submit an empty answer.
Mathematics
1 answer:
Mamont248 [21]2 years ago
3 0

The possible values for the number of whole hours clearing tables that she must work to meet her requirements is 2, 3 hours

<em><u>Solution:</u></em>

Amount earned in babysitting = $ 12 per hour

Amount earned in clearing tables = $ 8 per hour

In a given week, she can work a maximum of 17 total hours and must earn a minimum of $180

Sofia worked 14 hours babysitting

Therefore,

Amount earned at babysitting = 14 x 12 = 168

Thus, Sofia earned $ 168 at babysitting

Sofia must earn a minimum of $ 180

Remaining amount to be earned = 180 - 168 = 12

Thus, Sofia must earn $ 12 from clearing tables

Amount earned in clearing tables = $ 8 per hour

So, she must work for atleast 1.5 hours to get $ 12 from clearing tables

She can work a maximum of 17 total hours and Sofia worked 14 hours babysitting

Remaining is 17 - 14 = 3 hours

Thus possible values for the number of whole hours clearing tables that she must work to meet her requirements is 2 hours or 3 hours

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As can be read from your statement written "T, equals, start fraction, left parenthesis, d, minus, 15, right parenthesis, strt superscript, 2, end superscript, divided by, 300, end fraction, plus, 20", I hope your model equation is this :

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So lets find derivative of T function first

So first expand (d-15)^{2} as (d-15)(d-15)

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Now we will derivate each term here,300 in denominator is constant so that will come as it in in denominator.

To derivate terms in dx^{2} -30d +225 we will use power rule formula:

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For minimum we will put this derivative =0

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Now solve for d

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0 \times 300 = \frac{2d-30}{300} \times 300

0 = 2d-30

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For that simply plug 15 in d place in original T function equation

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Given

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