A number cube has six faces, numbered 1 to 6. John tossed two number cubes several times and added the numbers each time

Explain why the graphing calculator cannot be used to solve or approximate solutions to all polynomial equations.

Triss [41]

Did your explanation include the following?

Some polynomial equations have complex solutions.

Therefore, complex solutions cannot be found by graphing the related system or function in the Cartesian (x-y) plane.

Polynomial functions with all complex solutions do not have x-intercepts, and the related system of equations will not intersect.

6 0

2 years ago

Read 2 more answers

The Wilson family invited 100 relatives to their Christmas party. 90 guests had Dutch heritage, 80 had German heritage and 75 ha

givi [52]

They have 265 who claimed ancerysty

8 0

2 years ago

Your Mutual Fund was valued at $237,500. It has lost 6% per year for the last 3 years. What is its value today?

Makovka662 [10]

Answer:

The answer is C) $197,263.70

Step-by-step explanation:

It's losing 6% PER year for the last 3 year.

You can do what I did and take $237,500 and times it 0.06. Which should give you 14,250, that is how much is lost in year one.

So subtract 14,250 from 237,500, you should have $223,250 now.

Repeat the first step with $223,250 now, you times it by 0.06 again and you should get 13,395, you subtract that from $223,250.

You have $209,855 now, once again times that by 0.06 and you get 12,591.30. Subtract 12,591.30 from 209,855 and you should end up with $197,263.70

It's a long, simple method and I'm sure there is another method of solving this question, but this is an easy way to get the answer.

5 0

2 years ago

The weights of certain machine components are normally distributed with a mean of 8.01 g and a standard deviation of 0.06 g. Fin

Free_Kalibri [48]

Answer:

Option D) 7.90 g and 8.12 g

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8.01 g

Standard Deviation, σ = 0.06 g

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.03

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 8.01}{0.06})=0.03$

$= 1 -P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.03$

$=P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.97$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 8.01}{0.06} = 1.881\\\\x = 8.12$

Thus, 8.17 g separates the top 3% of the weights.

P(X < x)

$P( X < x) = P( z < \displaystyle\frac{x - 8.01}{0.06})=0.03$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 8.01}{0.06} = -1.881\\\\x = 7.90$

Thus, 7.90 separates the bottom 3% of the weights.

Thus, the correct answer is

Option D) 7.90 g and 8.12 g

7 0

2 years ago

What is the maximum vertical distance between the line y = x + 56 and the parabola y = x2 for −7 ≤ x ≤ 8?

atroni [7]

-7 and 8 are the solutions to the given equation system.
Therefore, the maximum distance between the y values of the two equations must lie exactly between their points of intersection. That is on x value:
x = (-7 + 8)/2 = 0.5
The maximum distance is:
y = 0.5 + 56 = 56.5
y = 0.5² = 0.25
56.5 - 0.25 = 56.25 units

5 0

2 years ago