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4vir4ik [10]
1 year ago
9

Mia enlarged a plan for an outdoor stage. The original plan is shown below. She dilated the outdoor stage by a scale factor of 4

with the center of dilation at the origin. Which ordered pair will be the coordinates of one of the new vertices? A (2,1) B (8,16) C (32,4) D (32,16)

Mathematics
2 answers:
garik1379 [7]1 year ago
5 0
Since you didn't give the original picture, I can only explain the process. Then, you need to select the correct point.

In a dilation, we multiply the coordinates by the scale factor. Take the points that you have and multiply them all by 4. Then, look for a point making your new coordinates.
yawa3891 [41]1 year ago
5 0

Answer:

D (32,16)

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.  Please see the attached photo.

In the photo, the four vertices are:

(-5,4)  by a scale factor of 4 (-20, 16)

(8, 4)  by a scale factor of 4 (32, 16)

(-6, -2)  by a scale factor of 4 (-24, -8)

(8, -2)   by a scale factor of 4 (31, -8)

So only D is correct.

Hope it will find you well.

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Elijah and Jonathan play on the same soccer team. They have played 3 of their 15,
Lynna [10]

Answer:

Only Elijah's model is correct

Step-by-step explanation:

The data given in the question tells us they have 12 games left on their soccer team. Each one of them tried to simulate the fact by creating some model which look like a balance between quantities.

Elijah placed 3 cubes of value 1 and a cube of value x on one side of a balance. On the other side, he placed 15 cubes of value 1. He was obviously modeling the fact that 15 cubes (games due to play in our case) should be equal to 3 cubes (games already played) plus the x numbers left to play

This model if perfect, since the only way to equilibrate the balance is setting x to 12, the games left to play

Jonathan used a table with 3 x's in a row and a 15 in the second row, trying to model the same situation. To our interpretation, this table doesn't show the number of games left to play. If we equate 3x = 15, we get x=5 which has nothing to do with the situation explained in the question, so this model is not correct.

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1 year ago
If PQ=RS, which of the following must be true?
maw [93]

<u>Answer:</u>

If PQ=RS then PQ and RS have the same length. Hence option D is correct

<u>Solution:</u>

Given that, pq = rs  

And, we have to find which of the given options are true.

<u><em>a) pq and rs form a straight angle </em></u>

We can’t decide the angle in between pq and rs just by the statement pq = rs.

So this statement is false.

<u><em>b) pq and rs form a zero angle. </em></u>

We can’t decide the angle in between pq and rs just by the statement pq = rs.

So this statement is false.

<u><em>c) pq and rs are same segment. </em></u>

If two things equal then there is no condition that both represents a single item.

So this statement is false.

<u><em>d) pq and rs have the same length </em></u>

As given that pq = rs, we can say that they will have the same length  

Hence, option d is true.

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2 years ago
a lunch stand makes a $.75 profit on each chef's salad and $1.20 profit on each caesar salad. On a typical weekday, it sells bet
tangare [24]

Answer:

<em>50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.</em>

Step-by-step explanation:

Suppose, the number of Chef's salad is x and the number of Caesar salad is y

On a typical weekday, it sells between 40 and 60 Chefs salads and between 35 and 50 Caesar salads.

So, the two constraints are:  40\leq x\leq 60 and  35\leq y\leq 50

The total number sold has never exceed 100 salads. So, another constraint will be:   x+y\leq 100

According to the graph of the constraints, the vertices of the common shaded region are:  (40,35), (60,35), (60,40), (50,50) and (40,50)   <em>(Refer to the attached image for the graph)</em>

The lunch stand makes a $.75 profit on each Chef's salad and $1.20 profit on each Caesar salad. So, the profit function will be:  P=0.75x+1.20y

For  (40, 35) ,   P=0.75(40)+1.20(35)=72

For  (60, 35) ,   P=0.75(60)+1.20(35)=87

For  (60, 40) ,   P=0.75(60)+1.20(40)=93

For  (50, 50) ,   P=0.75(50)+1.20(50)=97.5 <u><em>(Maximum)</em></u>

For  (40, 50) ,   P=0.75(40)+1.20(50)=90

Profit will be maximum when x=50 and y=50

Thus, 50 Chef's salads and 50 Caesar salads should be prepared in order to maximize profit.

6 0
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