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AnnZ [28]
2 years ago
5

Cynthia ran 17.5 laps in 38.5 minutes if she ran each lap at the same pace how long did it take her to run one full lap

Mathematics
1 answer:
marishachu [46]2 years ago
4 0

Answer:

2.2 minutes

Step-by-step explanation:

38.5 ÷ 17.5 = 2.2

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The product of a number,and 0.28 is 13.44. which equation matches this statement
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one day 2 babies were born in 1 hour home babie was 0.28LBS less heavier that the baby that was 13.44LBS whats the difference between the babies?

Step-by-step explanation:

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The length of the completed tunnel can be calculated using the equation . If the project will be completed 86 days after the TBM
bazaltina [42]
The y - intercept of an equation is the value of y when x is substituted with zero. From the given equation,
y = 25x + 225
Substituting,
y = (25)(0) + 225
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Thus, the y - intercept of the given equation is 225.
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The Taieri Plain in New Zealand is 6 feet below sea level (or –6 feet). If you are standing 3 feet above sea level, is your elev
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You would be 3ft above the sea level, if you are -6ft under the sea level and if you are standing 3ft “above” you would have to clime back up 9ft to get back to the positive’s which is “positive 3” so yes, your elevation will be opposite of the “plain” since you went to a -6 to a positive 3, with different numbers.
8 0
1 year ago
Diana sold 336 muffins at the bake sale.Bob sold 287 muffins.Bob estimates that he sold 50 fewer muffins than Diana.how did he e
malfutka [58]

Step-by-step explanation:

Since we have given that

Number of muffins Diana sold at the bake sale = 336

Number of muffins Bob sold at the bake sale = 287

Now, here we are using the method of estimation i.e. rounding the integers to nearest ones.

By estimation, we get

Number of muffins Diana sold at the bake sale = 340

Number of muffins Bob sold at the bake sale = 290

So,

Difference between them is given by

340-290\\=50

Hence, Bob sold 50 fewer muffins than Diana.

3 0
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We're testing the hypothesis that the average boy walks at 18 months of age (H0: p = 18). We assume that the ages at which boys
marusya05 [52]

Answer:

II. This finding is significant for a two-tailed test at .01.

III. This finding is significant for a one-tailed test at .01.

d. II and III only

Step-by-step explanation:

1) Data given and notation    

\bar X=19.2 represent the battery life sample mean    

\sigma=2.5 represent the population standard deviation    

n=25 sample size    

\mu_o =18 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

2) State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean battery life is equal to 18 or not for parta I and II:    

Null hypothesis:\mu = 18    

Alternative hypothesis:\mu \neq 18    

And for part III we have a one tailed test with the following hypothesis:

Null hypothesis:\mu \leq 18    

Alternative hypothesis:\mu > 18  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

3) Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{19.2-18}{\frac{2.5}{\sqrt{25}}}=2.4    

4) P-value    

First we need to calculate the degrees of freedom given by:  

df=n-1=25-1=24  

Since is a two tailed test for parts I and II, the p value would be:    

p_v =2*P(t_{(24)}>2.4)=0.0245

And for part III since we have a one right tailed test the p value is:

p_v =P(t_{(24)}>2.4)=0.0122

5) Conclusion    

I. This finding is significant for a two-tailed test at .05.

Since the p_v. We reject the null hypothesis so we don't have a significant result. FALSE

II. This finding is significant for a two-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

III. This finding is significant for a one-tailed test at .01.

Since the p_v >\alpha. We FAIL to reject the null hypothesis so we have a significant result. TRUE.

So then the correct options is:

d. II and III only

6 0
2 years ago
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