Answer:
The time of a commercial airplane is 280 minutes
Step-by-step explanation:
Let
x -----> the speed of a commercial airplane
y ----> the speed of a jet plane
t -----> the time that a jet airplane takes from Vancouver to Regina
we know that
The speed is equal to divide the distance by the time
y=2x ----> equation A
<u><em>The speed of a commercial airplane is equal to</em></u>
x=1,730/(t+140) ----> equation B
<u><em>The speed of a jet airplane is equal to</em></u>
y=1,730/t -----> equation C
substitute equation B and equation C in equation A
1,730/t=2(1,730/(t+140))
Solve for t
1/t=(2/(t+140))
t+140=2t
2t-t=140
t=140 minutes
The time of a commercial airplane is
t+140=140+140=280 minutes
Answer:
D) 15
Step-by-step explanation:
The sum of the interior angles of a polygon is given by

We have that, the sum of the interior angles of a polygon is
26 right angles. We want to find n, the number of sides.
We substitute into the formula to get:

Divide through by 90

Divide through by 2



G(h) h
12 3
8 5
4 7
0 9
Equation of the line:
slope = [12-0]/[3-9] = 12 / -6 = -2
g / [h - 9] = -2
g = -2(h-9)
g = -2h + 18
g = 18 -2h
Filling the tank ==> h = 0
g = 18 - 2(0) = 18
Answer: first option g = 18 -2 h; 18
Answer:
54 mph
Step-by-step explanation:
The answer should be Two and Three ...