2 years ago

Tomas has $45.00 to purchase favors for a party. If the favors are $3.75 each, how many favors can Tomas buy?

Mathematics

2 answers:

MariettaO [177]2 years ago

8 0

Answer:

Step-by-step explanation:

yessssssssssssssss sir its 12

elena-14-01-66 [18.8K]2 years ago

5 0

12 is right^^^^^^^^^^^^

You might be interested in

In 2009, a city with a population of 796,000 had 2,388 births. What is the number of births per 10,000 in the city?

Tom [10]

796,000/2388=10,000/x
796,000x= (2388*10,000)
796,000x/796,000=23,880,000/796,000
x=30 births

7 0

2 years ago

Sammy has a 10-foot ladder, which he needs to climb to reach the roof of his house. the roof is 12 feet above the ground. the ba

timama [110]

<span>Using the Pythagorean theorum we can solve this v a^2+b^2= c^2. A is the distance from base of house to ladder A= 1.5, c ifls length of ladder, c= 10. (1.5)^2 + ;b^2 = (10)^2. Solve for b. B= 9.88. 12 foot height of house - 9.88 feet to top of angled ladder = 2.11 from top of ladder to edge of roof</span>

6 0

2 years ago

Two pounds of sugar cost $1.40. How much sugar do you get per dollar? Round your answer to the nearest hundredth, if necessary.

Vsevolod [243]

Answer:

1.429 lbs per dollar of sugar

Step-by-step explanation:

multiply by 5 get 10 lbs of sugar for 7 dollars divide by 7 get 1.4285 round up

5 0

2 years ago

Frankie wants to build a path from one corner of his yard to the opposite corner. His yard measures 20 ft. x 32 ft. What will be

riadik2000 [5.3K]

Frankie's yard is a rectangle with the longer side = 32ft and the shorter side = 20ft. You want to find the length of the diagonal going through the rectangle. In essence, you basically have a triangle with two sides, one 32ft, the other 20ft, and you're looking for the hypotenuse.

Let's call a=32, b=20, and you're looking for the hypotenuse c. Use the Pythagorean theorem:
${a}^{2} + {b}^{2} = {c}^{2}$
Plug the numbers in to find c, the length of your path! So
$\sqrt{{32}^{2} + {20}^{2}} = 37.7$

4 0

1 year ago

Read 2 more answers

Using the U- Substitution u=sqrt(2x), integral form 2-8 dx/ sqrt(2x) + 1 is equivalent to ...

AleksAgata [21]

We will use u-substitute: $u= \sqrt{2x} , \frac{du}{dx}= \frac{1}{ \sqrt{2x} }= \frac{1}{u}$ Then for substitution:dx=u du. and integral becomes: $\int { \frac{u}{u+1} } \, du = \int { \frac{u+1-1}{u+1} } \, du= \int{1} \, du- \int { \frac{1}{u-1} } \, dx$ =u-ln(u+1)= $\sqrt{2x}-ln( \sqrt{2x}+1)$ . Now we will change the values of limits: $\sqrt{16}-ln( \sqrt{16}+1)-( \sqrt{4}-ln( \sqrt{4}+1))$ =4-ln(5)-2+ln(3)=2+ln(0,6)=2-0.51=1.49

8 0

2 years ago