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1 year ago

Tomas has $45.00 to purchase favors for a party. If the favors are $3.75 each, how many favors can Tomas buy?

Mathematics

2 answers:

MariettaO [177]1 year ago

8 0

Answer:

Step-by-step explanation:

yessssssssssssssss sir its 12

elena-14-01-66 [18.8K]1 year ago

5 0

12 is right^^^^^^^^^^^^

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Janice works at a cell phone company. She wants to make a presentation to her team about the features of a new phone. She makes

Advocard [28]

If 1 inch represents 0.5 centimeter, then 28 inches will represent 28 * 0.5 = 14 centimeters and 15 inches will represent 15 * 0.5 = 7.5 centimeters.

The actual dimensions of the phone is: the length is 14 centimeters and the width is 7.5 centimeters.

8 0

1 year ago

Read 2 more answers

Find the measure of b. A. 80 B. 70 C. 40 D. 20

BlackZzzverrR [31]

Answer:

40°

Step-by-step explanation:

e = 20°

d = 20°

c = 140°

b = 40°

8 0

2 years ago

Adita has two options for how to invest $1,000. Plan A: Put the $1,000 in an account that pays $100 per year. Plan B: Put the $1

cluponka [151]

Answer:

Plan A = 1000 dollars to be invested in an account that pays 100 dollars per year. (1000 + 100 = 1100 dollars in a year)

Plab B = 1000 dollars to be invested in an account that pays 5% interests per year (1000 * .05 = 50 => 1000 + 50 = 1050 dollars per year)

The correct answer is Plan A will be worth more than plan B after two years.

Step-by-step explanation:

Plan A = 1000 dollars to be invested in an account that pays 100 dollars per year. (1000 + 100 = 1100 dollars in a year)

Plab B = 1000 dollars to be invested in an account that pays 5% interests per year (1000 * .05 = 50 => 1000 + 50 = 1050 dollars per year)

3 0

1 year ago

There are 10 pots exposed in the shop, 2 of which have hidden defects. the customer buys two pieces. what is the probability tha

Tpy6a [65]

Check the tree diagram, of all the possible scenarios and the probabilities.

All the possible scenarios are:

1st.non defective, 2nd.non defective
1st.non defective, 2nd. defective
1st. defective, 2nd. non defective
1st. defective, 2nd. defective

consider the case 1st.non defective, 2nd.non defective

the probability that the first one is non defective is 8/10, since 8 out of 10 are non defective.

In this scenario, the second one is non defective as well. The probability for this to happen is 7/9, since now we have 7 non defective pots, and 9 in total.

This means that the probability of the first to be non defective, and the second non-defective is (8/10) * (7/9)=0.622

similarly we calculate the other cases, as shown in the picture.

P(at least one is defective)=
P(1st.non defective, 2nd. defective)+P(1st. defective, 2nd. non defective)+P(1st. defective, 2nd. defective)=
0.178+0.178+0.022=0.378

Answer: 0.378

8 0

1 year ago

Tickets for the baseball games were $2.50 for general admission and 50 cents for kids. If there were six times as many general a

Makovka662 [10]

There was 3000 general admission tickets sold and 500 kid ticket sold.

How did I get this?

First, we need to see what information we have.
$2.50 = General admission tickets = (G)
$0.50 = kids tickets = (K)
There were 6x as many general admission tickets sold as kids. G = 6K

We need two equations:
G = 6K
$2.50G + $.50K = $7750
Since, G = 6K we can substitute that into the 2nd equation.

2.50(6K) + .50K = 7750
Distribute 2.50 into the parenthesis

15K + .50K = 7750
combine like terms

15.50K = 7750
Divide both sides by 15.50, the left side will cancel out.

K = 7750/15.50
K = 500 tickets
So, 500 kid tickets were sold.

Plug K into our first equation (G = 6k)

G = 6*500
G = 3000 tickets

So, 3000 general admission tickets were sold,

Let's check this:

$2.50(3000 tickets) = $7500 (cost of general admission tickets)
$.50(500 tickets) = $250 (cost of general admission tickets)
$7500 + $250 = $7750 (total cost of tickets)

4 0

1 year ago