∆ABC has vertices at A(12, 8), B(4, 8), and C(4, 14). ∆XYZ has vertices at X(6, 6), Y(4, 12), and Z(10, 14). ∆MNO has vertices a
koban [17]
To get the length of each side,
use the distance formula with equation:
Distance = ((x2-x1)^2+(y2-y1)^2)^0.5
Solving
<span>AB = 8 units BC = 6 units AC = 10 units
</span><span>MN =8units NO = 6 units MO = 10 units
</span><span>XY = 6.32 units YZ = 6.32 units XZ = 8.94 units
</span>JK = 4.47 units KL = 4.47 units JL = 6 units
1 The
right answer is the letter b) triangle ABC and Triangle MNO are Congruent
<span>triangles
ABC and MNO are triangles that have the same lengths of its three sides.
</span>2 The answer is the letter c)
rotation
There
is a rotation of
90º about ABC and MNO the origin is B=N
B=N
C----------O
A----------M
<span>4(a^2 + 2b) - 2b
= 4a^2 + 8b - 2b
=</span> 4a^2 + 6b
Answer:
20
Step-by-step explanation:
that is right...........
Example of Phase of matter that show how characteristics of matter find application in our daily life??
