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Arada [10]
1 year ago
10

oint Q is plotted on the coordinate grid. Point P is at (40, −20). Point R is vertically above point Q. It is at the same distan

ce from point Q as point P is from point Q. Which of these shows the coordinates of point R and its distance from point Q? (5 points) On a coordinate grid from negative 50 to positive 50 in increments of 10, Point Q is plotted at the ordered pair negative 10, negative 20. Group of answer choices Point R is at (−10, −10), a distance of 30 units from point Q Point R is at (−10, −30), a distance of 50 units from point Q Point R is at (−10, 30), a distance of 50 units from point Q Point R is at (−10, 10), a distance of 30 units from point Q
Mathematics
2 answers:
JulsSmile [24]1 year ago
8 0

Answer:

The Awnser Is C

Step-by-step explanation:

Hope This Helps! Have A Great Day

zepelin [54]1 year ago
5 0

Answer:

I think it Is C 6..??

Step-by-step explanation:

I could me wrong IM srry also srry for late respond

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How much power is produced by a flashlight that has a voltage of 12 volts and a current of 6.5 × 10-2 amps?
Jlenok [28]

Answer:

0.78 Watts is correct answer.

Step-by-step explanation:

Formula:  

P=V*I  

=12*(6.5*10^-2)  

= 12*0.065  

=0.78 Watt.  

3 0
1 year ago
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In an anonymous survey 34 students reported the hours they studied for a statistics final exam. The histogram below shows the re
Darina [25.2K]

Answer:

c

Step-by-step explanation:

we have to use a mean to describe the center

4 0
2 years ago
In ΔABC, and m∠ABC = 90°. D and E are the midpoints of and , respectively. If the length of is 9 units, the length of is units a
jok3333 [9.3K]
This is an isosceles right triangle (AB = BC & ∠ B=90° - Given)
Then the angles at the base are equal and ∠ CAB = ∠ ACB = 45°

Theorem: Segment DE, joining the midpoints of 2 sides is:
1st) parallel to the 3rd side and
2nd) equal to half the measurement of the 3rd side
So if the 3rd side (hypotenuse) = 9 units, DE = 9/2 = 4.5 units
3 0
2 years ago
A member of a student team playing an interactive marketing game received the fol- lowing computer output when studying the rela
nirvana33 [79]

Answer:

p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91

So on this case for the significance level assumed \alpha=0.05 we see that p_v >\alpha so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

Step-by-step explanation:

Let's suppose that we have the following linear model:

y= \beta_o +\beta_1 X

Where Y is the dependent variable and X the independent variable. \beta_0 represent the intercept and \beta_1 the slope.  

In order to estimate the coefficients \beta_0 ,\beta_1 we can use least squares procedure.  

If we are interested in analyze if we have a significant relationship between the dependent and the independent variable we can use the following system of hypothesis:

Null Hypothesis: \beta_1 = 0

Alternative hypothesis: \beta_1 \neq 0

Or in other words we want to check is our slope is significant (X have an effect in the Y variable )

In order to conduct this test we are assuming the following conditions:

a) We have linear relationship between Y and X

b) We have the same probability distribution for the variable Y with the same deviation for each value of the independent variable

c) We assume that the Y values are independent and the distribution of Y is normal  

The significance level assumed on this case is \alpha=0.05

The standard error for the slope is given by this formula:

SE_{\beta_1}=\frac{\sqrt{\frac{\sum (y_i -\hat y_i)^2}{n-2}}}{\sqrt{\sum (X_i -\bar X)^2}}

Th degrees of freedom for a linear regression is given by df=n-2 since we need to estimate the value for the slope and the intercept.  

In order to test the hypothesis the statistic is given by:

t=\frac{\hat \beta_1}{SE_{\beta_1}}

The p value on this case would be given by:

p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91

So on this case for the significance level assumed \alpha=0.05 we see that p_v >\alpha so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

3 0
2 years ago
What additional information could you use to show that ΔSTU ≅ ΔVTU using SAS? Check all that apply.
Ugo [173]
I believe the correct answers are:

<span>UV = 14 ft and m∠TUV = 45°</span>
<span>ST = 20 ft, UV = 14 ft, and m∠UST = 98°

Or, in other words, Options A and D.
</span>
6 0
2 years ago
Read 2 more answers
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