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Arada [10]
2 years ago
10

oint Q is plotted on the coordinate grid. Point P is at (40, −20). Point R is vertically above point Q. It is at the same distan

ce from point Q as point P is from point Q. Which of these shows the coordinates of point R and its distance from point Q? (5 points) On a coordinate grid from negative 50 to positive 50 in increments of 10, Point Q is plotted at the ordered pair negative 10, negative 20. Group of answer choices Point R is at (−10, −10), a distance of 30 units from point Q Point R is at (−10, −30), a distance of 50 units from point Q Point R is at (−10, 30), a distance of 50 units from point Q Point R is at (−10, 10), a distance of 30 units from point Q
Mathematics
2 answers:
JulsSmile [24]2 years ago
8 0

Answer:

The Awnser Is C

Step-by-step explanation:

Hope This Helps! Have A Great Day

zepelin [54]2 years ago
5 0

Answer:

I think it Is C 6..??

Step-by-step explanation:

I could me wrong IM srry also srry for late respond

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Aaron drew the figure below for a school art project. What is the total area of the figure. Use the drop down menus to complete
Feliz [49]

Answer:

The trapezoid has a height of 3 inches, a shorter base measuring 2.75 inches, and a longer base measuring 4.25 inches. The total area of the entire figure is 33 square inches.

Step-by-step explanation:

I took the iready diagnostic :)

6 0
2 years ago
Read 2 more answers
The table gives estimates of the world population, in millions, from 1750 to 2000. (Round your answers to the nearest million.)
BaLLatris [955]

Answer:

A.) 1508 ; 1870

B.) 2083

C.) 3972

Step-by-step explanation:

General form of an exponential model :

A = A0e^rt

A0 = initial population

A = final population

r = growth rate ; t = time

1)

Using the year 1750 and 1800

Time, t = 1800 - 1750 = 50 years

Initial population = 790

Final population = 980

Let's obtain the growth rate :

980 = 790e^50r

980/790 = e^50r

Take the In of both sides

In(980/790) = 50r

0.2155196 = 50r

r = 0.2155196/50

r = 0.0043103

Using this rate, let predict the population in 1900

t = 1900 - 1750 = 150 years

A = 790e^150*0.0043103

A = 790e^0.6465588

A = 1508.0788 ; 1508 million people

In 1950;

t = 1950 - 1750 = 200

A = 790e^200*0.0043103

A = 790e^0.86206

A = 1870.7467 ; 1870 million people

2.)

Exponential model. For 1800 and 1850

Initial, 1800 = 980

Final, 1850 = 1260

t = 1850 - 1800 = 50

Using the exponential format ; we can obtain the rate :

1260 = 980e^50r

1260/980 = e^50r

Take the In of both sides

In(1260/980) = 50r

0.2513144 = 50r

r = 0.2513144/50

r = 0.0050262

Using the model ; The predicted population in 1950;

In 1950;

t = 1950 - 1800 = 150

A = 980e^150*0.0050262

A = 980e^0.7539432

A = 2082.8571 ; 2083 million people

3.)

1900 1650

1950 2560

t = 1900 - 1950 = 50

Using the exponential format ; we can obtain the rate :

2560 = 1650e^50r

2560/1650 = e^50r

Take the In of both sides

In(2560/1650) = 50r

0.4392319 = 50r

r = 0.4392319/50

r = 0.0087846

Using the model ; The predicted population in 2000;

In 2000;

t = 2000 - 1900 = 100

A = 1650e^100*0.0087846

A = 1650e^0.8784639

A = 3971.8787 ; 3972 million people

3 0
2 years ago
Based only on the information given in the diagram which congruence theorems or postulates could be givenas reasons why triangle
Evgesh-ka [11]
The  answer is C, E, and F on Apex
3 0
2 years ago
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Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?
REY [17]
<span>Which value of b will cause the quadratic equation x2 + bx + 5 = 0 to have two real number solutions?


–5</span>
5 0
2 years ago
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A bridge hand in which there is no card higher than a nine is called a Yarborough. Specify an appropriate sample space and deter
Vilka [71]

Answer:

The probability of Yarborough when you are randomly dealt 13 cards out of a well-shuffled deck of 52 card is 0.000547.

Step-by-step explanation:

The number of ways you  can choose a set of 13 different cards from a deck of 52 cards is given by 52P13.

Hence the unordered sample space has 52P13 equally likely outcomes. The number of outcomes with no card above a nine is 32P13.

This leads to the same value for the desired probability of a Yarborough:

32P13 / 52P13  = 0.000547.

3 0
2 years ago
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