A decagon has 10 sides.
It it is regular you can build 10 isosceles triangles from the center of the decagon to the 10 sides.
Each triangle has a common vertex where the angle of each triangle is 360° / 10 = 36°.
So each time that you rotate the decagon a multiple of 36° around the center you get an image that coincides with the original decagon.
If the letters are given clockwise:
- when you rotate 36° counter clockwise, the point A' (the image of A) will coincide with the point J.
- when you rotate 72° (2 times 36°) counter clockwise, the point A' will land on I.
- when you rotate 108° (3 times 36°) counter clockwise, the point A' will land on H.
- when you rotate 144° (4 times 36°) counter clockwise, the point A' will land on G.
- when you rotate 180° (5 times 36°) counter clockwise, the point A' will land on I.
- when you rotate 216° (6 times 36°) counter clockwise, the point A' will land on E.
- whn you rotate 252° (7 times 36°) counterclockwise, the point A' will coincide with D.
Add other 36° each time and A' will coincide successively with C, B and the same A.
The Venn Diagram that represents the problem is shown below
P(E|F) and P(F|E) are the conditional probability.
P(E|F) is given by P(E∩F) ÷ P(F) = ¹/₂ ÷ ¹/₂ = 1
P(F|E) is given by P(F∩E) ÷ P(E) = ¹/₂ ÷ ¹/₂ = 1
So going+return=1356
return is 284 lesss than going
return=-284+going
subsitute
going-284+going=1356
2going-284=1356
add 284 to both sides
2going=1640
divide both sides by 2
going=820
so we havve
return=-284+going
return=-284+820
return=536
answer is return=536 miles
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Answer:
Honestly i think i know which diagrams your talking about but if it there is an option that has 20 squares and only 15 are shaded then thats the one u choose I'm thinking that option is c
I hope this helps please mark me brainliest
