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rosijanka [135]
1 year ago
12

At the beginning of the school year, Jamie had $500 in her savings account. She wants to have at least $200 left in the account

at the end of the school year. Each week, she withdraws $30 for spending money. To determine how many weeks she can spend $30, Jamie wrote and solved this inequality. 500 − 30x ≥ 200 −500 −500 −30x ≥ −300 x ≥ 10 Review Jamie's work. What was her error? Jamie should have used the less than or equal to sign when writing the inequality. Jamie should have reversed the inequality when using the division property of inequality. Jamie should have added 500 to both sides. Jamie should have started by dividing by –30.
Mathematics
2 answers:
mario62 [17]1 year ago
8 0

Answer:

Jamie should have reversed the inequality when using the division property of inequality.

Step-by-step explanation:

Jamie wrote

500 − 30x ≥ 200

Subtract 500 from both sides

500-500-30x ≥ 200-500

-30x ≥ -300

Divide both sides by -30

x ≥ 10

Instead of reversing the inequality when using the division property of inequality

500 − 30x ≥ 200

Subtract 500 from both sides

500-500-30x ≥ 200-500

-30x ≥ -300

Divide both sides by -30

x <or= 10

Colt1911 [192]1 year ago
7 0

the answer is B i hope this helps

^_^

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We know that
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volume of </span><span>a rectangular pyramid=(1/3)*B*h-----> equation 2
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substitute equation 1 in equation 2
</span>volume of a rectangular pyramid=(1/3)*volume of a rectangular prism
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</span>volume of a rectangular pyramid=(1/3)*volume of a rectangular prism
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cones and cylinders

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4 0
1 year ago
A firm has a revenue function that can be represented by r (x)=700x-0.35x^2, where r (x) is the total revenue (in dollars) and x
Fudgin [204]

Answer:

How many units need to be sold to produce the maximum revenue? 1000 units

How many in dollars is the maximum revenue when the maximum of units are sold? $350,000

Step-by-step explanation:

We get max value of a function if we differentiate it and set it equal to 0.

We need to differentiate r(x) and set it equal to 0 and solve for x.

<u><em>That would be number of units sold to get max revenue.</em></u>

<u><em /></u>

<u>Then we take that "x" value and substitute into r(x) to get the max revenue amount.</u>

<u />

Before differentiating, we see the rules shown below:

f(x)=ax^n\\f'(x)=n*ax^{n-1}

Where

f'(x) is the differentiated function

Now, let's do the process:

r (x)=700x-0.35x^2\\r(x)=700-2*0.35x\\r(x)=700-0.7x\\0=700-0.7x\\0.7x=700\\x=1000

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The max revenue amount is $350,000

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