I'm assuming that by "opposite of 12", it means -12
If so, the answer would be 2
Answer:
The first part is C) The increase in loudness per centimeter is the same for both
The second part is A) Thor's
Step-by-step explanation:
First part:
<u>Whose loudness increases more per additional centimeter of height?</u>
C) The increase in loudness per centimeter is the same for both
Second part:
<u>Whose strike is louder when he strikes from a height of 40 centimeters?</u>
A) Thor's
I did it on Khan and it was correct.
Answer:
<h2>It must be shown that both j(k(x)) and k(j(x)) equal x</h2>
Step-by-step explanation:
Given the function j(x) = 11.6
and k(x) = 
, to show that both equality functions are true, all we need to show is that both j(k(x)) and k(j(x)) equal x,
For j(k(x));
j(k(x)) = j[(ln x/11.6)]
j[(ln (x/11.6)] = 11.6e^{ln (x/11.6)}
j[(ln x/11.6)] = 11.6(x/11.6) (exponential function will cancel out the natural logarithm)
j[(ln x/11.6)] = 11.6 * x/11.6
j[(ln x/11.6)] = x
Hence j[k(x)] = x
Similarly for k[j(x)];
k[j(x)] = k[11.6e^x]
k[11.6e^x] = ln (11.6e^x/11.6)
k[11.6e^x] = ln(e^x)
exponential function will cancel out the natural logarithm leaving x
k[11.6e^x] = x
Hence k[j(x)] = x
From the calculations above, it can be seen that j[k(x)] = k[j(x)] = x, this shows that the functions j(x) = 11.6 and k(x) = are inverse functions.
<span><u><em>First way:</em></u>
The easiest and simplest way is to <u>count by 1</u> starting from 82 till you reach 512.
<u>This will go as follows:</u>
82, 83, 84, 85, ........... , 510, 511, 512
<u><em>Second way:</em></u>
We can note that the two given numbers are even numbers. This means that the two numbers are divisible by 2.
Therefore, we can <u>count by 2</u> starting from 82 till we reach 512.
<u>This will go as follows:</u>
82, 84, 86, 88, ................... , 508, 510, 512
<u><em>Third way:</em></u>
We can note that the units digit in both numbers is the same (the digit is 2). This means that we can count from 82 till 512 by <u>adding 10 each time</u>.
<u>This will go as follows:</u>
82, 92, 102, 112, ......................, 492, 502, 512
Hope this helps :)</span>
