The answer is 1 gallon.
Miles per gallon(mpg) is computed by dividing the distance traveled by the how many gallons used. So you can derive a formula for how many gallons you would use given the mpg. You will end up with:

The problem asks for how many gallons of gas she will safe in a five-day work work week. So first you need to compute how many miles that would be.
54 miles/day x 5days =
270 milesSo in a five day work week, she will travel 270 miles.
Now to see how much gas she will save, compute how many gallons she will use up for each car, given the mpg of each and find the difference.
First model:30 mpg

This means that with the first model, she will have used up
9 gallons in a 5-day work week.
Second model: 27 mpg


This means that with the second model, she will have used up 10g in a 5-day work week.
Now for the last bit. How much will she save? You can get that by getting the difference of how many gallons each car would have used up.
10gallons - 9gallons = 1gSo she would have saved
1 gallon of gas if she buys the first car instead of the second.
Answer:
11/20 or 99/180 days
Step-by-step explanation:
55/100 converted to ?/180
180/100=1.8
so you would do the same on the numerator which is 55*1.8=99
99/180= 33/60=11/20
Swimmer a swims 100 meters, which is 100 1-meters, which is 100
(1 yards +3.37 inches) = 100 yards + 337 inches.
1 yard is 3 feet, so 100 yards are 300 feet.
100 in is 8.33 feet so
337 in is (337*8.33)/100=28.07 feet
Swimmer b swims 100 yards, which is 300 feet
Swimmer a swam 28.07 feet.
Answer:
The confidence interval for the difference in proportions is

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.
Step-by-step explanation:
We have to construct a confidence interval for the difference of proportions.
The difference in the sample proportions is:

The estimated standard error is:

The z-value for a 95% confidence interval is z=1.96.
Then, the lower and upper bounds are:

The confidence interval for the difference in proportions is

<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>
No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.
This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.