A + B + C = 476
A = 3B + 6
C = B + 45
now its just a matter of subbing..
A + B + C = 476
(3B + 6) + B + (B + 45) = 476...combine like terms
5B + 51 = 476
5B = 476 - 51
5B = 425
B = 425/5
B = 85 <== team B scored 85
A = 3B + 6
A = 3(85) + 6
A = 255 + 6
A = 261 <=== team A scored 261
C = B + 45
C = 85 + 45
C = 130 <=== team C scored 130
I say it is C. Basically I just eliminate the potential answered down. A could not be the one since not all student in 2nd period got 100% and average students got below 95%. B cannot be it since both box plot have the same median. I do not think D is it because of how the answer is told. "The 4th period class should get the reward. Their lowest score is an outlier, and should be thrown out," it sound childish and makeing a joke to put "and should be thrown out." I may be wrong but that is my opinion. The relatively the best and reasonable answer is C.
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The range of a function is representative of the values on the y-axis. In this case, the graph will contain distance on the y-axis at is the dependent variable, while the independent variable is time.
We know that the minimum value of the distance will be 0, given that there can be no negative distance. Moreover, the maximum value is 26.2 miles, since the marathon will then be over. Therefore, a good range for the situation will be 0-27 miles.
Answer:
D. -6m²n² + 10m²n + 8mn² - 10mn
Step-by-step explanation:
(-7mn + 8mn² - 8m²n²) + (10m²n + 2m²n² - 3mn)
Apply the distributive property to remove the parentheses
-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn
Combine like terms together and arrange in standard form
-7mn + 8mn² - 8m²n² + 10m²n + 2m²n² - 3mn
-8m²n² + 2m²n² + 10m²n + 8mn² - 7mn - 3mn
-6m²n² + 10m²n + 8mn² - 10mn
