Answer:
Step-by-step explanation:
Rate of leakage, R(t) = 1400 e^0.06t gallons/h
fraction remains , S(t) = e^(-0.32t)
initial contaminant = 1000 gallon
gallons contaminant present after t hour is S(t) R(t)
G(t) = S(t) R(t)


Put t = 18 hours

Taking log on both the sides
ln G = ln 1400 - 0.26 x 18
ln G = 7.244 - 4.68
ln G = 2.564
G = 13 gallons
Answer:
168
Step-by-step explanation:
60+16+8 is 84
84 times 2 is 168
Mark me as brainliest if this helps!
Answer:
the new scale is the same length as the original scale
It would be 50 because the 5 is in the tens spot