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2 years ago

Which equation is y=3(x-2)^2-(x-5)^2 rewritten in vertex form?

Mathematics

2 answers:

snow_lady [41]2 years ago

6 0

that answer is totally incomplete

Misha Larkins [42]2 years ago

3 0

The question does not present the options, but this does not interfere with the resolution

we have that
y=3(x-2)²-(x-5)²
y=3(x²-4x+4)-(x²-10x+25)
y=3x²-12x+12-x²+10x-25
y=(3x²-x²)+(-12x+10x)+(12-25)
y=2x²-2x-13
y+13=2x²-2x
y+13=2(x²-x)
y+13+0.50=2(x²-x+0.25)
y+13.50=2(x-0.5)²------> this is the equation in the vertex form

the vertex is the point (0.5,-13.50)

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(b) 3m - 2n=19 5m + 7n=11

Korvikt [17]

3m-2n=19

5m+7n=11

21m-14n=133

10m+14n=22

Now add equations

31m=155

m=5

Now let's find n

3×5-2n=19

-2n=4

n=-2

Answer: (5; -2)

6 0

2 years ago

Can someone help please??

Nady [450]

Answer:

The scores in order from least likely to most likely is 8, 3, 4, and 5.

Step-by-step explanation:

1. Calculate the probability of the spinner adding up to 1, 2, 3, 4, .... 8

You will get:

2 (1/16)

3 (2/16)

4 (3/16)

5 (4/16)

6 (3/16)

7 (2/16)

8 (1/16)

2. Given the scores from the problem, the probability of each number is 3 (2/16), 4 (3/16), 5 (4/16), and 8 (1/16).

3. With this, we can determine the scores in order from least likely to most likely is 8, 3, 4, and 5.

8 0

2 years ago

The graph of f(x) = StartRoot x EndRoot is reflected over the y-axis. Use the graphing calculator to graph this reflection. Whic

labwork [276]

Answer:

(–81, 9), (–36, 6), (–1, 1) are the correct three points.

Step-by-step explanation:

Given the function:

$f(x) =\sqrt x$

Please refer to the attached image.

The green line shows the graph of actual function.

It is reflected over y axis.

The reflected graph is shown in black color in attached image.

When reflected over y axis, the sign of variable $x$ changes from Positive to Negative.

So, the resultant function becomes:

$f(x)=\sqrt{-x}$

i.e. we will have to give the values of x as negative now.

so, the options in which value of x is negative are the possible answers only.

The possible answers are:

(–81, 9), (–36, 6), (–1, 1) and

(–49, 7), (–18, 9), (–1, 1)

Now, we will check the square root function condition.

In the 2nd option, (–18, 9) does not satisfy the condition.

So, the correct answer is:

(–81, 9), (–36, 6), (–1, 1)

7 0

2 years ago

Samuel was riding in the back seat of the station wagon on the way home after a long and tiring day at the

ki77a [65]

Answer: One fourth of the entire trip.

Step-by-step explanation:

The initial distance is D.

" He fell asleep halfway home."

Then he fells asleep when the distance between his actual position and his house was half of D, or:

D/2.

"He didn't wake up until he still had half as far to go as he had already

gone while asleep."

So he wakes up when his actual position is a fourth of the initial distance:

(D/2)/2 = D/4.

Then if the entire trip has a distance D, and he was sleeping between:

D/2 - D/4 = 2D/4 - D/4 = D/4.

in a trip of a distance D, he was asleep a distance of D/4.

Then, returning to the question:

How much of the entire trip home was Samuel asleep?

This is equal to the quotient between the distance that he travels asleep and the total distance:

r = (D/4)/D = 1/4.

Then he was asleep in 1/4 of the entire trip.

7 0

2 years ago

Katy had two choices of routes to get her to work. She wanted to choose the route that would get her to work fastest, on average

zmey [24]

Answer:

D. There is not enough evidence at the 5% significance level to indicate that one route gets Katy to work faster, on average, since 0 falls within the bounds of the confidence interval.

Step-by-step explanation:

At 5% confidence level, Katy found difference in mean commuting times (Route 1-Route 2) in minutes as (-1,9).

Since no difference in means (0 min) falls within the confidence level (-1,9), we can not reject the hypothesis that there is no difference in mean commuting times when using Route1 or Route2.

A higher significance level(10% etc) may lead a shorter confidence interval leaving 0 outside and may reach a conclusion that Route1 takes longer than Route2

4 0

2 years ago