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Ivan
1 year ago
8

On commencing employment a man is paid a salary of $7200 per annum and receives annual increments of $350. Determine his salary

in the 9th year and calculate the total he will have in the first 12years.
Mathematics
1 answer:
Marina CMI [18]1 year ago
8 0

Answer:

Step-by-step explanation:

From the question, we can form an equation like: S = 7200 + 350X

where S is the salary and X is year.

1. His salary in the 9th year, means X=9, so we substitute 9 into the equation to find S = 7200 +350 (9) = 10350

2. The total he will have in the first 12years, we have:

Sum of first n terms of an <em><u>AP: S =(n/2)[2a + (n- 1)d]</u></em> where a is the value of the 1st term, here a is 7200 and d = 350 the common difference between terms

=> S = (12/2)[2*7200 + (12- 1)350] = 109500

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(b) A department store has 7,000 charge accounts. The comptroller takes a random sample of 36 of
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Answer:

a.0.8664

b. 0.23753

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Step-by-step explanation:

The comptroller takes a random sample of 36 of the account balances and calculates the standard deviation to be N42.00. If the actual mean (1) of the account balances is N175.00, what is the probability that the sample mean would be between

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We solve the above question using z score formula

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σ is the population standard deviation = N42

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a. Between N164.50 and N185.50?

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Probability value from Z-Table:

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For x = N185.50

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Probability value from Z-Table:

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= 0.93319 - 0.066807

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b. greater than N180.00?

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P(x>180) = 1 - P(x<180) = 0.23753

c. less than N168.00?

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z = -7/42/6

z = -7/7

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Probability value from Z-Table:

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