All categories

2 years ago

1) The line plot shows the part of a gallon of water that Jill drank each day last

Mathematics

1 answer:

Natali5045456 [20]2 years ago

5 0

Answer:

3 1/8

Step-by-step explanation:

1. You can add the 2 halves together making 1

2. Then add a 3/4 and one 1/4 together making another 1

3. With the remaining two 1/4s, that makes another half. So at the moment, you have 2 1/2

4. Convert 2 1/2 to eighths. 2 4/8

5. Finally add one 5/8.

So the answer is 3 1/8

You might be interested in

Which explains why Ramone’s equation has no solution?

kvv77 [185]

The matrices must be the same size

Good luck

8 0

2 years ago

Read 2 more answers

N 1928, when the high jump was first introduced as a women's sport at the Olympic Games, the winning jump for women was 70.0 inc

n200080 [17]

Omg ! I’m not sure at all

4 0

2 years ago

Repeated student samples. Of all freshman at a large college, 16% made the dean’s list in the current year. As part of a class p

Dima020 [189]

Answer:

a) p-hat (sampling distribution of sample proportions)

b) Symmetric

c) σ=0.058

d) Standard error

e) If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

Step-by-step explanation:

a) This distribution is called the sampling distribution of sample proportions (p-hat).

b) The shape of this distribution is expected to somewhat normal, symmetrical and centered around 16%.

This happens because the expected sample proportion is 0.16. Some samples will have a proportion over 0.16 and others below, but the most of them will be around the population mean. In other words, the sample proportions is a non-biased estimator of the population proportion.

c) The variability of this distribution, represented by the standard error, is:

$\sigma=\sqrt{p(1-p)/n}=\sqrt{0.16*0.84/40}=0.058$

d) The formal name is Standard error.

e) If we divided the variability of the distribution with sample size n=90 to the variability of the distribution with sample size n=40, we have:

$\frac{\sigma_{90}}{\sigma_{40}}=\frac{\sqrt{p(1-p)/n_{90}} }{\sqrt{p(1-p)/n_{40}}}}= \sqrt{\frac{1/n_{90}}{1/n_{40}}}=\sqrt{\frac{1/90}{1/40}}=\sqrt{0.444}= 0.667$

If we increase the sample size from 40 to 90 students, the standard error becomes two thirds of the previous standard error (se=0.667).

0 0

2 years ago

Subject On-Time Assignment Submission On-Time Arrival to Class Physics 89.7% 82.3% Math 88.2% 88.7% Chemistry 89.4% 83.1% Biolog

Alekssandra [29.7K]

Answer:

D. insufficient data

Step-by-step explanation:

We need to know the number of assignments in each class before we can tell the probability of interest.

If we assume the same number of assignments in each class, then 25.1% of on-time assignments were in physics. We note this is not an answer choice, further confirming we have insufficient data.

7 0

2 years ago

The Metro theater has 20 rows of seats with 18 seats in each row Tickets cost $5 The theaters income in dollars if all seats are

Olin [163]

Answer: $1800

The theater income will be the total of audience multiplied by the ticket cost. To answer this question, you need to determine the total audience count. Assuming all the seats are occupied then:
Total audience= row of seats x seats/ row = 20x18 people = 360 people

After that the income would be:
Income = audience x ticket cost
Income= 360 people x $5 / people= $1800

3 0

1 year ago